本文整理汇总了VB.NET中System.String.LastIndexOfAny方法的典型用法代码示例。如果您正苦于以下问题：VB.NET String.LastIndexOfAny方法的具体用法？VB.NET String.LastIndexOfAny怎么用？VB.NET String.LastIndexOfAny使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.String的用法示例。
在下文中一共展示了String.LastIndexOfAny方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的VB.NET代码示例。
示例1: Sample
' Sample for String.LastIndexOfAny(Char[], Int32)
_
Class Sample
Public Shared Sub Main()
Dim br1 As String = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
Dim br2 As String = "0123456789012345678901234567890123456789012345678901234567890123456"
Dim str As String = "Now is the time for all good men to come to the aid of their party."
Dim start As Integer
Dim at As Integer
Dim target As String = "is"
Dim anyOf As Char() = target.ToCharArray()
start =(str.Length - 1) / 2
Console.WriteLine("The last character occurrence from position {0} to 0.", start)
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str)
Console.Write("A character in '{0}' occurs at position: ", target)
at = str.LastIndexOfAny(anyOf, start)
If at > - 1 Then
Console.Write(at)
Else
Console.Write("(not found)")
End If
Console.Write("{0}{0}{0}", Environment.NewLine)
End Sub
End Class输出：
The last character occurrence from position 33 to 0. 0----+----1----+----2----+----3----+----4----+----5----+----6----+- 0123456789012345678901234567890123456789012345678901234567890123456 Now is the time for all good men to come to the aid of their party. A character in 'is' occurs at position: 12
示例2: Sample
' Sample for String.LastIndexOfAny(Char[], Int32, Int32)
_
Class Sample
Public Shared Sub Main()
Dim br1 As String = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
Dim br2 As String = "0123456789012345678901234567890123456789012345678901234567890123456"
Dim str As String = "Now is the time for all good men to come to the aid of their party."
Dim start As Integer
Dim at As Integer
Dim count As Integer
Dim target As String = "aid"
Dim anyOf As Char() = target.ToCharArray()
start =(str.Length - 1) * 2 / 3
count =(str.Length - 1) / 3
Console.WriteLine("The last character occurrence from position {0} for {1} characters.", start, count)
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str)
Console.Write("A character in '{0}' occurs at position: ", target)
at = str.LastIndexOfAny(anyOf, start, count)
If at > - 1 Then
Console.Write(at)
Else
Console.Write("(not found)")
End If
Console.Write("{0}{0}{0}", Environment.NewLine)
End Sub
End Class输出：
The last character occurrence from position 44 for 22 characters. 0----+----1----+----2----+----3----+----4----+----5----+----6----+- 0123456789012345678901234567890123456789012345678901234567890123456 Now is the time for all good men to come to the aid of their party. A character in 'aid' occurs at position: 27
示例3: Sample
' Sample for String.LastIndexOfAny(Char[])
_
Class Sample
Public Shared Sub Main()
Dim br1 As String = "0----+----1----+----2----+----3----+----4----+----5----+----6----+-"
Dim br2 As String = "0123456789012345678901234567890123456789012345678901234567890123456"
Dim str As String = "Now is the time for all good men to come to the aid of their party."
Dim start As Integer
Dim at As Integer
Dim target As String = "is"
Dim anyOf As Char() = target.ToCharArray()
start = str.Length - 1
Console.WriteLine("The last character occurrence from position {0} to 0.", start)
Console.WriteLine("{1}{0}{2}{0}{3}{0}", Environment.NewLine, br1, br2, str)
Console.Write("A character in '{0}' occurs at position: ", target)
at = str.LastIndexOfAny(anyOf)
If at > - 1 Then
Console.Write(at)
Else
Console.Write("(not found)")
End If
Console.Write("{0}{0}{0}", Environment.NewLine)
End Sub
End Class输出：
The last character occurrence from position 66 to 0. 0----+----1----+----2----+----3----+----4----+----5----+----6----+- 0123456789012345678901234567890123456789012345678901234567890123456 Now is the time for all good men to come to the aid of their party. A character in 'is' occurs at position: 58