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VB.NET String.Contains方法代码示例

本文整理汇总了VB.NET中System.String.Contains方法的典型用法代码示例。如果您正苦于以下问题:VB.NET String.Contains方法的具体用法?VB.NET String.Contains怎么用?VB.NET String.Contains使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在System.String的用法示例。


在下文中一共展示了String.Contains方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的VB.NET代码示例。

示例1: Example

Class Example
   Public Shared Sub Main()
      Dim s1 As String = "The quick brown fox jumps over the lazy dog"
      Dim s2 As String = "fox"
      Dim b As Boolean = s1.Contains(s2)
      Console.WriteLine("'{0}' is in the string '{1}': {2}",
                        s2, s1, b)
      If b Then
          Dim index As Integer = s1.IndexOf(s2)
          If index >= 0 Then
             Console.WriteLine("'{0} begins at character position {1}",
                               s2, index + 1)
          End If
       End If
   End Sub
End Class
开发者ID:VB.NET开发者,项目名称:System,代码行数:16,代码来源:String.Contains

输出:

fox' is in the string 'The quick brown fox jumps over the lazy dog': True
fox begins at character position 17

示例2: StringExtensions

' 导入命名空间
Imports System.Runtime.CompilerServices

Module StringExtensions
   <Extension()>
   Public Function Contains(str As String, substring As String, 
                            comp As StringComparison) As Boolean
      If substring Is Nothing Then
         Throw New ArgumentNullException("substring", 
                                         "substring cannot be null.")
      Else If Not [Enum].IsDefined(GetType(StringComparison), comp)
         Throw New ArgumentException("comp is not a member of StringComparison",
                                     "comp")
      End If                               
      Return str.IndexOf(substring, comp) >= 0                      
   End Function
End Module
开发者ID:VB.NET开发者,项目名称:System,代码行数:17,代码来源:String.Contains

示例3: Example

Public Module Example
   Public Sub Main
      Dim s As String = "This is a string."
      Dim sub1 As String = "this"
      Console.WriteLine("Does '{0}' contain '{1}'?", s, sub1)
      Dim comp As StringComparison = StringComparison.Ordinal
      Console.WriteLine("   {0:G}: {1}", comp, s.Contains(sub1, comp))
      
      comp = StringComparison.OrdinalIgnoreCase
      Console.WriteLine("   {0:G}: {1}", comp, s.Contains(sub1, comp))
   End Sub
End Module
开发者ID:VB.NET开发者,项目名称:System,代码行数:12,代码来源:String.Contains

输出:

Does 'This is a string.' contain 'this'?
Ordinal: False
OrdinalIgnoreCase: True


注:本文中的System.String.Contains方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。