本文整理汇总了VB.NET中System.Math.Exp方法的典型用法代码示例。如果您正苦于以下问题：VB.NET Math.Exp方法的具体用法？VB.NET Math.Exp怎么用？VB.NET Math.Exp使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类System.Math的用法示例。
在下文中一共展示了Math.Exp方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的VB.NET代码示例。
示例1: ExpDemo
' Example for the Math.Exp( Double ) method.
Module ExpDemo
Sub Main()
Console.WriteLine( _
"This example of Math.Exp( Double ) " & _
"generates the following output." & vbCrLf)
Console.WriteLine( _
"Evaluate [e ^ ln(X) == ln(e ^ X) == X] " & _
"with selected values for X:")
UseLnExp(0.1)
UseLnExp(1.2)
UseLnExp(4.9)
UseLnExp(9.9)
Console.WriteLine( vbCrLf & _
"Evaluate these identities with selected values for X and Y:")
Console.WriteLine(" (e ^ X) * (e ^ Y) = e ^ (X + Y)")
Console.WriteLine(" (e ^ X) ^ Y = e ^ (X * Y)")
Console.WriteLine(" X ^ Y = e ^ (Y * ln(X))")
UseTwoArgs(0.1, 1.2)
UseTwoArgs(1.2, 4.9)
UseTwoArgs(4.9, 9.9)
End Sub
' Evaluate logarithmic/exponential identity with a given argument.
Sub UseLnExp(arg As Double)
' Evaluate e ^ ln(X) = ln(e ^ X) = X.
Console.WriteLine( _
vbCrLf & " Math.Exp(Math.Log({0})) = {1:E16}" + _
vbCrLf & " Math.Log(Math.Exp({0})) = {2:E16}", _
arg, Math.Exp(Math.Log(arg)), Math.Log(Math.Exp(arg)))
End Sub
' Evaluate exponential identities that are functions of two arguments.
Sub UseTwoArgs(argX As Double, argY As Double)
' Evaluate (e ^ X) * (e ^ Y) = e ^ (X + Y).
Console.WriteLine( _
vbCrLf & "Math.Exp({0}) * Math.Exp({1}) = {2:E16}" + _
vbCrLf & " Math.Exp({0} + {1}) = {3:E16}", _
argX, argY, Math.Exp(argX) * Math.Exp(argY), _
Math.Exp((argX + argY)))
' Evaluate (e ^ X) ^ Y = e ^ (X * Y).
Console.WriteLine( _
" Math.Pow(Math.Exp({0}), {1}) = {2:E16}" + _
vbCrLf & " Math.Exp({0} * {1}) = {3:E16}", _
argX, argY, Math.Pow(Math.Exp(argX), argY), _
Math.Exp((argX * argY)))
' Evaluate X ^ Y = e ^ (Y * ln(X)).
Console.WriteLine( _
" Math.Pow({0}, {1}) = {2:E16}" + _
vbCrLf & "Math.Exp({1} * Math.Log({0})) = {3:E16}", _
argX, argY, Math.Pow(argX, argY), _
Math.Exp((argY * Math.Log(argX))))
End Sub
End Module 'ExpDemo输出：
Evaluate [e ^ ln(X) == ln(e ^ X) == X] with selected values for X: Math.Exp(Math.Log(0.1)) = 1.0000000000000001E-001 Math.Log(Math.Exp(0.1)) = 1.0000000000000008E-001 Math.Exp(Math.Log(1.2)) = 1.2000000000000000E+000 Math.Log(Math.Exp(1.2)) = 1.2000000000000000E+000 Math.Exp(Math.Log(4.9)) = 4.9000000000000012E+000 Math.Log(Math.Exp(4.9)) = 4.9000000000000004E+000 Math.Exp(Math.Log(9.9)) = 9.9000000000000004E+000 Math.Log(Math.Exp(9.9)) = 9.9000000000000004E+000 Evaluate these identities with selected values for X and Y: (e ^ X) * (e ^ Y) = e ^ (X + Y) (e ^ X) ^ Y = e ^ (X * Y) X ^ Y = e ^ (Y * ln(X)) Math.Exp(0.1) * Math.Exp(1.2) = 3.6692966676192444E+000 Math.Exp(0.1 + 1.2) = 3.6692966676192444E+000 Math.Pow(Math.Exp(0.1), 1.2) = 1.1274968515793757E+000 Math.Exp(0.1 * 1.2) = 1.1274968515793757E+000 Math.Pow(0.1, 1.2) = 6.3095734448019331E-002 Math.Exp(1.2 * Math.Log(0.1)) = 6.3095734448019344E-002 Math.Exp(1.2) * Math.Exp(4.9) = 4.4585777008251705E+002 Math.Exp(1.2 + 4.9) = 4.4585777008251716E+002 Math.Pow(Math.Exp(1.2), 4.9) = 3.5780924170885260E+002 Math.Exp(1.2 * 4.9) = 3.5780924170885277E+002 Math.Pow(1.2, 4.9) = 2.4433636334442981E+000 Math.Exp(4.9 * Math.Log(1.2)) = 2.4433636334442981E+000 Math.Exp(4.9) * Math.Exp(9.9) = 2.6764450551890982E+006 Math.Exp(4.9 + 9.9) = 2.6764450551891015E+006 Math.Pow(Math.Exp(4.9), 9.9) = 1.1684908531676833E+021 Math.Exp(4.9 * 9.9) = 1.1684908531676829E+021 Math.Pow(4.9, 9.9) = 6.8067718210957060E+006 Math.Exp(9.9 * Math.Log(4.9)) = 6.8067718210956985E+006