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Python Zappa.invoke_lambda_function方法代码示例

本文整理汇总了Python中zappa.zappa.Zappa.invoke_lambda_function方法的典型用法代码示例。如果您正苦于以下问题:Python Zappa.invoke_lambda_function方法的具体用法?Python Zappa.invoke_lambda_function怎么用?Python Zappa.invoke_lambda_function使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在zappa.zappa.Zappa的用法示例。


在下文中一共展示了Zappa.invoke_lambda_function方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_invoke_lambda_function

# 需要导入模块: from zappa.zappa import Zappa [as 别名]
# 或者: from zappa.zappa.Zappa import invoke_lambda_function [as 别名]
    def test_invoke_lambda_function(self, session):
        z = Zappa(session)
        z.credentials_arn = 'arn:aws:iam::724336686645:role/ZappaLambdaExecution'

        function_name = 'django-helloworld-unicode'
        payload = '{"event": "hello"}'
        response = z.invoke_lambda_function(function_name, payload)
开发者ID:ConfidentCannabis,项目名称:Zappa,代码行数:9,代码来源:tests.py

示例2: handle

# 需要导入模块: from zappa.zappa import Zappa [as 别名]
# 或者: from zappa.zappa.Zappa import invoke_lambda_function [as 别名]
    def handle(self, *args, **options):
        """
        Execute the command.

        """

        if not options.has_key('environment') or len(options['environment']) < 2:
            print("You must call deploy with an environment name and command. \n python manage.py invoke <environment> <command>")
            return

        from django.conf import settings
        if not 'ZAPPA_SETTINGS' in dir(settings):
            print("Please define your ZAPPA_SETTINGS in your settings file before deploying.")
            return

        zappa_settings = settings.ZAPPA_SETTINGS

        # Set your configuration
        project_name = settings.BASE_DIR.split(os.sep)[-1]
        api_stage = options['environment'][0]
        if api_stage not in zappa_settings.keys():
            print("Please make sure that the environment '" + api_stage + "' is defined in your ZAPPA_SETTINGS in your settings file before deploying.")
            return

        lambda_name = project_name + '-' + api_stage

        # Make your Zappa object
        zappa = Zappa()

        # Invoke it!
        command = {"command": ' '.join(options['environment'][1:])}
        response = zappa.invoke_lambda_function(lambda_name, json.dumps(command), invocation_type='RequestResponse')

        if response.has_key('LogResult'):
            print(base64.b64decode(response['LogResult']))
        else:
            print(response)
            import pdb
            pdb.set_trace()

        return
开发者ID:Doerge,项目名称:django-zappa,代码行数:43,代码来源:invoke.py


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