本文整理汇总了Python中zappa.zappa.Zappa.get_api_url方法的典型用法代码示例。如果您正苦于以下问题：Python Zappa.get_api_url方法的具体用法？Python Zappa.get_api_url怎么用？Python Zappa.get_api_url使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类zappa.zappa.Zappa的用法示例。
在下文中一共展示了Zappa.get_api_url方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: test_get_api_url
# 需要导入模块: from zappa.zappa import Zappa [as 别名]
# 或者: from zappa.zappa.Zappa import get_api_url [as 别名]
def test_get_api_url(self, session):
z = Zappa(session)
z.credentials_arn = 'arn:aws:iam::724336686645:role/ZappaLambdaExecution'
url = z.get_api_url('Spheres-demonstration')示例2: handle
# 需要导入模块: from zappa.zappa import Zappa [as 别名]
# 或者: from zappa.zappa.Zappa import get_api_url [as 别名]
def handle(self, *args, **options):
"""
Execute the command.
"""
if not options.has_key('environment'):
print("You must call deploy with an environment name. \n python manage.py deploy <environment>")
return
from django.conf import settings
if not 'ZAPPA_SETTINGS' in dir(settings):
print("Please define your ZAPPA_SETTINGS in your settings file before deploying.")
return
zappa_settings = settings.ZAPPA_SETTINGS
# Set your configuration
project_name = settings.BASE_DIR.split(os.sep)[-1]
api_stage = options['environment'][0]
if api_stage not in zappa_settings.keys():
print("Please make sure that the environment '" + api_stage + "' is defined in your ZAPPA_SETTINGS in your settings file before deploying.")
return
# Make your Zappa object
zappa = Zappa()
# Load environment-specific settings
s3_bucket_name = zappa_settings[api_stage]['s3_bucket']
settings_file = zappa_settings[api_stage]['settings_file']
if '~' in settings_file:
settings_file = settings_file.replace('~', os.path.expanduser('~'))
if not os.path.isfile(settings_file):
print("Please make sure your settings_file is properly defined.")
return
custom_settings = [
'http_methods',
'parameter_depth',
'integration_response_codes',
'method_response_codes',
'role_name',
'aws_region'
]
for setting in custom_settings:
if zappa_settings[api_stage].has_key(setting):
setattr(zappa, setting, zappa_settings[api_stage][setting])
# Load your AWS credentials from ~/.aws/credentials
zappa.load_credentials()
# Create the Lambda zip package (includes project and virtualenvironment)
# Also define the path the handler file so it can be copied to the zip root for Lambda.
current_file = os.path.dirname(os.path.abspath(inspect.getfile(inspect.currentframe())))
handler_file = os.sep.join(current_file.split(os.sep)[0:-2]) + os.sep + 'handler.py'
lambda_name = project_name + '-' + api_stage
zip_path = zappa.create_lambda_zip(lambda_name, handler_file=handler_file)
# Add this environment's Django settings to that zipfile
with zipfile.ZipFile(zip_path, 'a') as lambda_zip:
lambda_zip.write(settings_file, 'zappa_settings.py')
lambda_zip.close()
# Upload it to S3
zip_arn = zappa.upload_to_s3(zip_path, s3_bucket_name)
# Register the Lambda function with that zip as the source
# You'll also need to define the path to your lambda_handler code.
lambda_arn = zappa.update_lambda_function(s3_bucket_name, zip_path, lambda_name)
# Get the URL!
endpoint_url = zappa.get_api_url(lambda_name)
# Finally, delete the local copy our zip package
os.remove(zip_path)
# Remove the uploaded zip from S3, because it is now registered..
zappa.remove_from_s3(zip_path, s3_bucket_name)
print("Your updated Zappa deployment is live!")
return