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Python Zappa.create_iam_roles方法代码示例

本文整理汇总了Python中zappa.zappa.Zappa.create_iam_roles方法的典型用法代码示例。如果您正苦于以下问题:Python Zappa.create_iam_roles方法的具体用法?Python Zappa.create_iam_roles怎么用?Python Zappa.create_iam_roles使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在zappa.zappa.Zappa的用法示例。


在下文中一共展示了Zappa.create_iam_roles方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_create_iam_roles

# 需要导入模块: from zappa.zappa import Zappa [as 别名]
# 或者: from zappa.zappa.Zappa import create_iam_roles [as 别名]
 def test_create_iam_roles(self, session):
     z = Zappa(session)
     arn = z.create_iam_roles()
     self.assertEqual(arn, "arn:aws:iam::123:role/{}".format(z.role_name))
开发者ID:ConfidentCannabis,项目名称:Zappa,代码行数:6,代码来源:tests.py

示例2: handle

# 需要导入模块: from zappa.zappa import Zappa [as 别名]
# 或者: from zappa.zappa.Zappa import create_iam_roles [as 别名]
    def handle(self, *args, **options):
        """
        Execute the command.

        """
        if not options.has_key('environment'):
            print("You must call deploy with an environment name. \n python manage.py deploy <environment>")
            return

        from django.conf import settings
        if not 'ZAPPA_SETTINGS' in dir(settings):
            print("Please define your ZAPPA_SETTINGS in your settings file before deploying.")
            return

        zappa_settings = settings.ZAPPA_SETTINGS

        # Set your configuration
        project_name = settings.BASE_DIR.split(os.sep)[-1]
        api_stage = options['environment'][0]
        if api_stage not in zappa_settings.keys():
            print("Please make sure that the environment '" + api_stage + "' is defined in your ZAPPA_SETTINGS in your settings file before deploying.")
            return

        # Make your Zappa object
        zappa = Zappa()

        # Load environment-specific settings
        s3_bucket_name = zappa_settings[api_stage]['s3_bucket']
        vpc_config = zappa_settings[api_stage].get('vpc_config', {})
        memory_size = zappa_settings[api_stage].get('memory_size', 512)
        settings_file = zappa_settings[api_stage]['settings_file']
        if '~' in settings_file:
            settings_file = settings_file.replace('~', os.path.expanduser('~'))
        if not os.path.isfile(settings_file):
            print("Please make sure your settings_file is properly defined.")
            return

        custom_settings = [
            'http_methods', 
            'parameter_depth',
            'integration_response_codes',
            'method_response_codes',
            'role_name',
            'aws_region'
        ]
        for setting in custom_settings:
            if zappa_settings[api_stage].has_key(setting):
                setattr(zappa, setting, zappa_settings[api_stage][setting])

        # Load your AWS credentials from ~/.aws/credentials
        zappa.load_credentials()

        # Make sure the necessary IAM execution roles are available
        zappa.create_iam_roles()

        # Create the Lambda zip package (includes project and virtualenvironment)
        # Also define the path the handler file so it can be copied to the zip root for Lambda.
        current_file =  os.path.dirname(os.path.abspath(inspect.getfile(inspect.currentframe())))
        handler_file = os.sep.join(current_file.split(os.sep)[0:-2]) + os.sep + 'handler.py'
        lambda_name = project_name + '-' + api_stage
        zip_path = zappa.create_lambda_zip(lambda_name, handler_file=handler_file)

        # Add this environment's Django settings to that zipfile
        with open(settings_file, 'r') as f:
            contents = f.read()
            all_contents = contents
            if not zappa_settings[api_stage].has_key('domain'):
                script_name = api_stage
            else:
                script_name = ''

            if not "ZappaMiddleware" in all_contents:
                print("\n\nWARNING!\n")
                print("You do not have ZappaMiddleware in your remote settings's MIDDLEWARE_CLASSES.\n")
                print("This means that some aspects of your application may not work!\n\n")
            
            all_contents = all_contents + '\n# Automatically added by Zappa:\nSCRIPT_NAME=\'/' + script_name + '\'\n'
            f.close()

        with open('zappa_settings.py', 'w') as f:
            f.write(all_contents)

        with zipfile.ZipFile(zip_path, 'a') as lambda_zip:
            lambda_zip.write('zappa_settings.py', 'zappa_settings.py')
            lambda_zip.close()

        os.unlink('zappa_settings.py') 

        # Upload it to S3
        zip_arn = zappa.upload_to_s3(zip_path, s3_bucket_name)

        # Register the Lambda function with that zip as the source
        # You'll also need to define the path to your lambda_handler code.
        lambda_arn = zappa.create_lambda_function(bucket=s3_bucket_name,
                                                  s3_key=zip_path,
                                                  function_name=lambda_name,
                                                  handler='handler.lambda_handler',
                                                  vpc_config=vpc_config,
                                                  memory_size=memory_size)

#.........这里部分代码省略.........
开发者ID:codingjoe,项目名称:django-zappa,代码行数:103,代码来源:deploy.py


注:本文中的zappa.zappa.Zappa.create_iam_roles方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。