本文整理汇总了Python中table.Table.get_style方法的典型用法代码示例。如果您正苦于以下问题：Python Table.get_style方法的具体用法？Python Table.get_style怎么用？Python Table.get_style使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类table.Table的用法示例。
在下文中一共展示了Table.get_style方法的5个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: stem
# 需要导入模块: from table import Table [as 别名]
# 或者: from table.Table import get_style [as 别名]
def stem(self, a_type = 'preview', xkcd = False, force = False,
expanded = True, fmt = 'latex'):
"""
Parameters:
----------
a_type : String ('preview', 'MC')
Is this for testing / preview? If so set to true.
expanded : Boolean
If true, the equation is fully expanded and the student must
get the equation into normal form.
"""
kwargs = {
'a_type':a_type
}
prob = Hyperbola()
if prob in self.done:
return self.stem(**kwargs)
else:
self.done.add(prob)
self.count += 1
if a_type == 'preview':
question_stem = "<br><h2>Question</h2><br>"
else:
question_stem = ""
if expanded:
const = (prob.a**2) * (prob.b **2)
question_stem += 'Find the normal form of the hyperbola given by the \
equation $$%s = 0$$ and use this \
to select the correct graph of the given hyperbola.' \
% ( sym.latex(const * (prob.expr.expand() - 1)))
else:
question_stem += 'Select the correct graph of the hyperbola given\
by the equations: $$%s = 1$$' % (prob.latex)
ans = prob.show(path=self.path, xkcd = xkcd, force = force)
if a_type == 'preview':
explanation = "<br><h2>Explanation</h2><br>"
else:
explanation = ""
explanation += prob.explanation(path=self.path + "/explanation",
a_type = a_type, fmt = fmt,
expanded = expanded,
xkcd = xkcd)
errors = self.gen_errors(prob, force = force, xkcd = xkcd)
errors = [ans] + errors
distractors = [html_image(er, preview = (a_type == 'preview'),
width = 300, height = 300)
for er in errors]
if a_type == 'preview':
data = [[dist] for dist in distractors]
tb = Table(data, row_headers = ["Answer"] + ["Distractor"] * 4)
return question_stem + explanation + Table.get_style() + \
tb.html()
elif a_type == 'MC':
if fmt == 'latex':
question_stem = question_stem.replace("<div ","<p ")\
.replace("</div>","</p>")
explanation = explanation.replace("<div ","<p ")\
.replace("</div>","</p>")
distractors = [err.replace("<div ","<p ")\
.replace("</div>","</p>") for err in errors]
question_stem = ' '.join(question_stem.split())
distractors = [' '.join(err.split()) for err in errors]
explanation = ' '.join(explanation.split()) + "\n"
return tools.fully_formatted_question(question_stem, explanation,
answer_choices=distractors)示例2: explanation
# 需要导入模块: from table import Table [as 别名]
# 或者: from table.Table import get_style [as 别名]
def explanation(self, path = 'explanations',
expanded = True, a_type = 'preview',
force = False, xkcd = False, fmt = 'latex'):
"""
Provides an explanation of the hyperbola.
Parameters: (Largely shared with show)
-----------
path : str
The output directory for image files
file_name : str
The name of output file without extension.
a_type : Strint ('MC', 'preview')
If 'preview', then set up for previewing.
fmt : String ('html', 'latex')
If 'latex' us MathJax, if 'html' use CSS tables.
"""
if fmt == 'html':
ex = Table.get_style()
else:
ex = ""
file_name = path + "/" + self.url + ".png"
if a_type == 'preview':
file_name = file_name.replace('%2','%252')
const = self.a ** 2 * self.b **2
x_part = const*(self(x, self.k).expand() - self(0, self.k))
y_part = const*(self(self.h, y).expand() - self(self.h, 0))
rhs = const - const*self(0, 0)
# The following is an attempt to avoid lots of code duplication.
if self.trans == 'x':
X = x
Y = y
X_part = x_part
Y_part = y_part
HH = self.h
KK = self.k
TX = 1
TY = 0
else:
X = y
Y = x
X_part = y_part
Y_part = x_part
HH = self.k
KK = self.h
TX = 0
TY = 1
# To reduce typing
A = self.a
B = self.b
H = self.h
K = self.k
C = self.c
k, h, a, b, c = sym.symbols('k h a b c')
gcd_X = sym.gcd(X_part.collect(X).coeff(X,1), X_part.collect(X).coeff(X,2))
gcd_Y = sym.gcd(Y_part.collect(Y).coeff(Y,1), Y_part.collect(Y).coeff(Y,2))
b_X = X_part.collect(X).coeff(X,1)/gcd_X
b_Y = -Y_part.collect(Y).coeff(Y,1)/gcd_Y
if expanded:
ex += "The first step to finding the graph of $$%s = 0$$ is\
to find the normal form of the equation." \
% sym.latex((const*(self(x, y) - 1)).expand())
ex += " To begin move the constant term to the right hand side. \
This gives: $$(%s) + (%s) = %s$$" \
% (sym.latex(x_part), sym.latex(y_part), rhs)
ex += "Next factor common factors from the $_x$_ and $_y$_ terms to get: \
$$%s(%s) - %s(%s) = %s$$" \
% (gcd_X if gcd_X != 1 else "", sym.latex(X_part/gcd_X),
gcd_Y if gcd_Y != 1 else "", sym.latex(-Y_part/gcd_Y), rhs)
ex += "Now complete the squares: \
$$%s\\left(%s %s\\right) \
- %s\\left(%s %s\\right) = \
%s %s %s$$"\
% (gcd_X if gcd_X != 1 else "", sym.latex(X_part/gcd_X),
"+ \\left(\\frac{%s}{2}\\right)^2" % b_X if b_X != 0 else "",
gcd_Y if gcd_Y != 1 else "", sym.latex(-Y_part/gcd_Y),
"+ \\left(\\frac{%s}{2}\\right)^2" % b_Y if b_Y != 0 else "",
rhs,
"+ %s\\left(\\frac{%s}{2}\\right)^2" % (gcd_X, b_X) if b_X != 0 else "",
"- %s\\left(\\frac{%s}{2}\\right)^2" % (gcd_Y, b_Y) if b_Y != 0 else "")
ex += "This simplifies to: $$%s\\left(%s\\right)^2 - %s\\left(%s\\right)^2 = %s$$" \
% (gcd_X if gcd_X != 1 else "",
sym.latex(X + b_X/2),
gcd_Y if gcd_Y != 1 else "",
#.........这里部分代码省略.........
示例3: stem
# 需要导入模块: from table import Table [as 别名]
# 或者: from table.Table import get_style [as 别名]
def stem(self, context = None, table = None, q_type = None,
a_type = 'preview', force = False, fmt = 'html'):
"""
This will generate a problem for $\chi^2$ goodness of fit.
Parameters:
----------
context : context object
This describes the problem. A default context is used if this is
none.
table : string ['hist', 'table']
Display t_dist as a table (html/latex) or as a histogram.
q_type : string [None, 'STAT', 'HT', 'CI']
If None randomly choose. If 'STAT' just compute the chi2 statistic
and the degrees of freedom. If 'HT, compute the p-value for the
data and determine whether or not reject the null hypothesis. If
'CI' compute the confidence interval.
a_type : string
This is eithe "MC" or "preview" for now
fmt : String ['html', 'latex']
Use nice CSS/HTML (responsive) or plain LaTeX (static)
Notes:
-----
The default here is to simulate a roll of a die 30 times and record the
frequency of values. The :math`\chi^2` test should test whether the die
is fair at an :math:`alpha`
level of 5%.
"""
kwargs = {
'context': context,
'table': table,
'q_type': q_type,
'fmt': fmt,
'a_type': a_type
}
if q_type is None:
q_type = random.choice(['STAT', 'HT', 'PVAL'])
if table == None:
table = random.choice(['table', 'hist'])
if context == None:
context = Chi2GoodnessOfFitData()
if not context.is_valid:
warnings.warn("Context had invalid cell counts.")
return
# Generate unique name
q_name = hash(context)
self.cache.add(q_name)
self.hist = str(q_name) + "_hist.png"
self.solution_plot = str(q_name) + "_plot.png"
style = None
if a_type == 'preview':
question_stem = "<h2>Question</h2><br>"
else:
question_stem = ""
if fmt == 'html':
question_stem += Table.get_style()
question_stem += "<div class='par'>" + context.story + "</div>\n"
if table == 'table':
if fmt == 'html':
tbl = context.observed.html()
question_stem += tbl
else:
tbl = context.observed.latex()
question_stem += tbl
elif table == 'hist':
fname = context.hist(path = self.path, force = force)
img = html_image(fname, width = '300px',
preview = (a_type == 'preview'))
if style is None:
style = Table.get_style()
question_stem += style
question_stem +="""
<div class='outer-container-rk'>
<div class='centering-rk'>
<div class='container-rk'>
<figure>
%s
<figcaption>%s</figcaption>
</figure>
</div>
</div>
#.........这里部分代码省略.........
示例4: gen_ctx
# 需要导入模块: from table import Table [as 别名]
# 或者: from table.Table import get_style [as 别名]
def gen_ctx():
ctx = Chi2GoodnessOfFitData(seed = seed)
#Here we sample from a non-uniform distribution for the die!
ctx1_args = {
'o_dist':[1/5, 1/5, 1/5, 1/5, 1/10, 1/10],
'alternative':"The die is not fair.",
'note':"""
For this problem the truth is tha the die is not fair. \
If you accepted H<sub>0</sub>, then this is a <strong>miss</strong>
(Type II error).
"""
}
ctx1 = Chi2GoodnessOfFitData(seed = seed, **ctx1_args)
######################################
# Pass the pigs game: Due to embedding the table in the story
# this one is a little harder to set up. The problem is that this
# pollutes namespace for future contexts.
# Append _ to avoid namespace pollution
_outcomes = ['Pink', 'Dot', 'Razorback', 'Trotter',
'Snouter', 'Leaning Jowler']
_t_dist = [.35, .30, .20, .10, .04, .01]
tb = Table(_t_dist, col_headers = _outcomes,
row_headers = ['Position', 'Expected Frequency'])
if fmt == 'html':
styles = Table.get_style()
tbl = tb.html()
else:
styles = ""
tbl = tb.latex()
_s_size = random.randint(20, 30) * 10
ctx2_args = {
'outcome_type':'Position',
'outcomes':_outcomes,
't_dist':_t_dist,
's_size':_s_size,
'story':"""Pass The Pigs® is a game from Milton-Bradley™
which is essentially a dice game, except that instead of dice
players toss small plastic pigs that can land in any of 6
positions. For example, you roll a 'trotter' if the pig falls
standing on all 4 legs. It is claimed that the distribution
for the 6 positions are:
{styles}
{tbl}
To test this you toss a pig {s_size} times and get the observed
frequencies below:
""".format(styles = styles, tbl = tbl, s_size = _s_size),
'null':"The observed values of the positions of the pigs agrees \
with the expected distribution.",
'alternative':"The observed values of the positions of the pigs \
differs from what should be the case if the expected distribution\
was correct.",
'note':"""
In this case the observed data was sampled from the given
distribution. So if the null hypothesis is rejected, this
is <string>a Type-I error</strong> or <strong>a false
positive</strong>.
"""
}
ctx2 = Chi2GoodnessOfFitData(seed = seed, **ctx2_args)
###########################################
## 11.2 from text
s_size = random.randint(5, 10) * 10
ctx3_args = {
'outcomes':['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday',
'Friday', 'Saturday'],
't_dist':np.ones(7) * 1/7,
's_size':s_size,
'a_level': random.choice([0.1,0.01,0.05]),
'outcome_type':'Day of Week',
'story':"""
Teachers want to know which night each week their students are
doing most of their homework. Most teachers think that students
do homework equally throughout the week. Suppose a random sample
of %s students were asked on which night of the week they
did the most homework. The results were distributed as in
""" % s_size,
'null':"Students are equally likely to do the majority of their \
homework on any of the seven nights of the week.",
'alternative':"Students are more likely to do the majority of their \
homework on certain nights rather than others."
}
ctx3 = Chi2GoodnessOfFitData(seed = seed, **ctx3_args)
return [ctx, ctx1, ctx2, ctx3]示例5: stem
# 需要导入模块: from table import Table [as 别名]
# 或者: from table.Table import get_style [as 别名]
def stem(self, context = None, q_type = None, a_type = 'preview',
force = False):
"""
This will generate a problem for $\chi^2$ test of homogeneity.
Parameters:
----------
context : Chi2TestOfHomogeneity object
This describes the problem. A default context is used if this is
none.
q_type : string [None, 'STAT', 'HT', 'CI']
If None randomly choose. If 'STAT' just compute the chi2 statistic
and the degrees of freedom. If 'HT, compute the p-value for the
data and determine whether or not reject the null hypothesis. If
'CI' compute the confidence interval.
force : Boolean
If true force egineration of images.
a_type : string
This is eithe "MC" or "preview" for now
"""
kwargs = {
'context': context,
'q_type': q_type,
'a_type': a_type,
'force': force
}
if q_type is None:
q_type = random.choice(['STAT', 'HT', 'PVAL'])
if context == None:
context = Chi2TestOfHomogeneityData()
if not context.is_valid:
warnings.warn("Context had invalid cell counts.")
return
# Generate unique name
q_name = hash(context)
self.cache.add(q_name)
self.hist = str(q_name) + ".png"
self.solution_plot = str(q_name) + "_sol.png"
style = None
if a_type == 'preview':
question_stem = "<h2>Question</h2><br>"
else:
question_stem = ""
if fmt == 'html':
question_stem += Table.get_style()
question_stem += "<div class='par'>" + context.story + "</div>\n"
if fmt == 'html':
tbl = context.observed_table.html()
else:
tbl = context.observed_table.latex()
question_stem += "\n" + tbl + "\n"
num_rows = len(context.rows)
num_cols = len(context.cols)
df = context.df
chi2eq = "$$\\chi^2_{%s}=\\sum_{i=1}^{%s}\\sum_{j=1}^{%s}\
\\frac{(O_{i,j}-E_{i,j})^2}{E_{i,j}}\
= %.3g$$" % (df, num_rows, num_cols, context.chi2_stat)
if q_type == 'STAT':
question_stem += "Compute the $_\\chi^2$_-statistic and degrees \
of freedom for the given observations."
elif q_type == 'PVAL':
question_stem += """The $_\\chi^2$_ statistic is
{chi2eq}
Use this information to find the degrees of freedom (df) and the
$_p\\text{{-value}} = P(\\chi^2_{{{df}}} > {chi2:.3g})$_.
""".format(chi2eq=chi2eq, df = 'df', chi2=context.chi2_stat)
elif q_type == 'HT':
question_stem += """The degrees of freedom are $_df =
({num_cols} -1)({num_rows} -1) =
{df}$_ and the $_\\chi^2$_ statistic is {chi2eq}
Use this information to conduct a hypothesis test with
$_\\alpha = {a_level}$_. Choose the answer that best captures
the null hypothesis and conclusion.
""".format(num_cols = num_cols, num_rows = num_rows, df = df,
chi2eq = chi2eq,
a_level = context.a_level)
#.........这里部分代码省略.........