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Python Polygon.overlaps方法代码示例

本文整理汇总了Python中shapely.geometry.Polygon.overlaps方法的典型用法代码示例。如果您正苦于以下问题:Python Polygon.overlaps方法的具体用法?Python Polygon.overlaps怎么用?Python Polygon.overlaps使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在shapely.geometry.Polygon的用法示例。


在下文中一共展示了Polygon.overlaps方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_prepared_predicates

# 需要导入模块: from shapely.geometry import Polygon [as 别名]
# 或者: from shapely.geometry.Polygon import overlaps [as 别名]
def test_prepared_predicates():
    # check prepared predicates give the same result as regular predicates
    polygon1 = Polygon([
        (0, 0), (0, 1), (1, 1), (1, 0), (0, 0)
    ])
    polygon2 = Polygon([
        (0.5, 0.5), (1.5, 0.5), (1.0, 1.0), (0.5, 0.5)
    ])
    point2 = Point(0.5, 0.5)
    polygon_empty = Polygon()
    prepared_polygon1 = PreparedGeometry(polygon1)
    for geom2 in (polygon2, point2, polygon_empty):
        assert polygon1.disjoint(geom2) == prepared_polygon1.disjoint(geom2)
        assert polygon1.touches(geom2) == prepared_polygon1.touches(geom2)
        assert polygon1.intersects(geom2) == prepared_polygon1.intersects(geom2)
        assert polygon1.crosses(geom2) == prepared_polygon1.crosses(geom2)
        assert polygon1.within(geom2) == prepared_polygon1.within(geom2)
        assert polygon1.contains(geom2) == prepared_polygon1.contains(geom2)
        assert polygon1.overlaps(geom2) == prepared_polygon1.overlaps(geom2)
开发者ID:Toblerity,项目名称:Shapely,代码行数:21,代码来源:test_prepared.py


注:本文中的shapely.geometry.Polygon.overlaps方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。