本文整理汇总了Python中rediscluster.StrictRedisCluster.publish方法的典型用法代码示例。如果您正苦于以下问题：Python StrictRedisCluster.publish方法的具体用法？Python StrictRedisCluster.publish怎么用？Python StrictRedisCluster.publish使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类rediscluster.StrictRedisCluster的用法示例。
在下文中一共展示了StrictRedisCluster.publish方法的3个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: RedisPubSubHelper
# 需要导入模块: from rediscluster import StrictRedisCluster [as 别名]
# 或者: from rediscluster.StrictRedisCluster import publish [as 别名]
class RedisPubSubHelper():
def __init__(self):
# redis连接对象
self.__conn = StrictRedisCluster(startup_nodes=redis_nodes, decode_responses=True)
def publish(self, channel, message):
# redis对象的publish方法(发布)
# 往指定的频道中发布信息
self.__conn.publish(channel, message)
return True
def subscribe(self, channel):
# 返回了一个发布订阅的对象
pub = self.__conn.pubsub()
# 订阅指定频道
pub.subscribe(channel)
pub.parse_response()
return pub示例2: StrictRedisCluster
# 需要导入模块: from rediscluster import StrictRedisCluster [as 别名]
# 或者: from rediscluster.StrictRedisCluster import publish [as 别名]
from rediscluster import StrictRedisCluster
startup_nodes = [{"host": "192.168.1.168", "port": "7000"}]
rc = StrictRedisCluster(startup_nodes=startup_nodes, decode_responses=True)
ps = rc.pubsub()
ps.subscribe(['foo', 'bar'])
rc.publish('foo', 'hello foo from python')
rc.publish('bar', 'hello bar from python')示例3: int
# 需要导入模块: from rediscluster import StrictRedisCluster [as 别名]
# 或者: from rediscluster.StrictRedisCluster import publish [as 别名]
actualMessage = int(message['data'])
print "%s%sReceived %s" % (' '*26, '\t'*shard, actualMessage)
if LastReceivedMessage+1 != actualMessage:
print "Missed %s messages" %(actualMessage-LastReceivedMessage-1)
LastReceivedMessage = actualMessage
#p.psubscribe(**{'my-*': my_handler}) # throws an error
p.subscribe(**{'0': my_handler})
p.subscribe(**{'1': my_handler})
p.subscribe(**{'2': my_handler})
p.subscribe(**{'3': my_handler})
p.subscribe(**{'4': my_handler})
p.subscribe(**{'5': my_handler})
p.get_message() # to see that there was a subscription
LastReceivedMessage = -1
r.publish('0', LastReceivedMessage+1)
p.get_message()
thread = p.run_in_thread(sleep_time=0.001)
COUNT = 1000
SLEEP = 0.1
message_id = 1
print 'LastReceivedMessage=',LastReceivedMessage
sleep(SLEEP)
print 'LastReceivedMessage=',LastReceivedMessage
try:
while message_id <= COUNT:
shard = message_id % 6
key = 'key' + str(shard)
payload = str(message_id)