本文整理汇总了Python中multiprocessing.Manager.remove方法的典型用法代码示例。如果您正苦于以下问题：Python Manager.remove方法的具体用法？Python Manager.remove怎么用？Python Manager.remove使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类multiprocessing.Manager的用法示例。
在下文中一共展示了Manager.remove方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: KarnaughMap
# 需要导入模块: from multiprocessing import Manager [as 别名]
# 或者: from multiprocessing.Manager import remove [as 别名]
#.........这里部分代码省略.........
n.flag = False
for j in range(0, len(a.values) ):
if(j!=(x-1)):
n.values.append(a.values[j] )
else:
n.values.append( 2 )
#/* Mark that a node is part of a larger node */
a.flag=True
b.flag=True
#/* Check if that block already exists in the list */
exist=False
for c in self.blocks:
if(n.values==c.values):
exist=True
if(not exist):
self.blocks.append(n )
def CleanProcess():
for process in ProcessList:
process.join()
for process in ProcessList:
jn = resultQueue.get()
for n in jn.newblocks:
exist = False
for c in self.blocks:
if(n.values==c.values):
exist=True
if(not exist):
self.blocks.append(n )
for b in jn.removeblocks:
for c in self.blocks:
if(b.values==c.values):
self.blocks.remove(c)
""" Check for special case that all cells in the map are the same """
a=1
for i in range(0,self.height):
if(a==0):
break
for j in range(0,self.width):
if( self.kmap[(j, i)]!=self.kmap[(0, 0)] ):
a=0
break
if(a==1):
#/* Clear the list so that all those nodes with one item are deleted */
#self.blocks=Manager().list()
self.blocks=[]
# If there are only zeros in the map there's nothing to solve
if (self.kmap[(0, 0)]==0):
return
else:
# If there are only ones, solution is one element as big as the map
n=KarnaughNode()
n.numberOfItems = self.width*self.height
for j in range(0,self.numberOfVariables):
n.values.append( 2 )
self.blocks.append(n )
return