本文整理汇总了Python中models.History.next_location方法的典型用法代码示例。如果您正苦于以下问题：Python History.next_location方法的具体用法？Python History.next_location怎么用？Python History.next_location使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类models.History的用法示例。
在下文中一共展示了History.next_location方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: move
# 需要导入模块: from models import History [as 别名]
# 或者: from models.History import next_location [as 别名]
def move():
p_entry = History.query.descending('mongo_id').first()
n_entry = History()
n_entry = p_entry
print p_entry.next_location.geocode[0]
print p_entry.next_location.geocode[1]
print p_entry.suggested_location.geocode[0]
print p_entry.suggested_location.geocode[1],
print p_entry.suggested_location.geocode[0] == p_entry.next_location.geocode[0]
#if the bot is not moving
if p_entry.status is False:
print "Fitz Owen is not moving, and.."
#if the bot has got a new suggestion, then move move move yo
if p_entry.next_location.geocode != p_entry.suggested_location.geocode:
print "there is a suggested destination :" + p_entry.suggested_location.name
n_entry.status = True
n_entry.previous_location = p_entry.next_location
n_entry.next_location = p_entry.suggested_location
distance = gcd(n_entry.previous_location.geocode[0], n_entry.previous_location.geocode[1], n_entry.next_location.geocode[0], n_entry.next_location.geocode[1])
n_entry.distance = distance
n_entry.number_of_segments = int(distance / p_entry.speed)
if (distance / p_entry.speed) < 1:
n_entry.number_of_segments = 1
print "Now moving towards" + n_entry.next_location.name +"..."
else :
print "okay, not moving"
#if the bot is approaching the destination..
elif p_entry.status is True:
if p_entry.segment is p_entry.number_of_segments:
print "got there!"
#then stop, and calibrate the location, reset
n_entry.status = False
n_entry.current_location = p_entry.next_location
n_entry.segment = 1
#Okay, now let's move..
else:
print "moving.."
lon = (p_entry.next_location.geocode[0] - p_entry.previous_location.geocode[0]) / p_entry.number_of_segments
lat = (p_entry.next_location.geocode[1] - p_entry.previous_location.geocode[1]) / p_entry.number_of_segments
xy = (p_entry.current_location.geocode[0]+lon,p_entry.current_location.geocode[1]+lat)
n_entry.current_location.geocode = xy
n_entry.segment = p_entry.segment + 1
print n_entry.segment
print n_entry.number_of_segments
n_entry.current_time = str(datetime.datetime.now())
n_entry.save()