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Python Mesh.discretize方法代码示例

本文整理汇总了Python中mesh.Mesh.discretize方法的典型用法代码示例。如果您正苦于以下问题:Python Mesh.discretize方法的具体用法?Python Mesh.discretize怎么用?Python Mesh.discretize使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在mesh.Mesh的用法示例。


在下文中一共展示了Mesh.discretize方法的3个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1:

# 需要导入模块: from mesh import Mesh [as 别名]
# 或者: from mesh.Mesh import discretize [as 别名]
if  __name__ == "__main__":

    from bases import ElementToBasis,Legendre
    from segments import Line,Arc
    from quadrules import GaussQuadrature
    from kernels import Identity,AcousticDoubleLayer
    from mesh import Domain,Mesh
    from assembly import assembleIdentity, assembleMatrix, projRhs, assembleElement

    k=10
    circle=Arc(0,0,0,2*numpy.pi,.5)
    circle2=Arc(2,0,0,2*numpy.pi,.5)
    d=Domain([circle])
    d2=Domain([circle2])
    mesh=Mesh([d])
    mesh.discretize(3)
    quadrule=GaussQuadrature(5,3,0.15)
    mToB=Legendre.legendreBasis(mesh,2)
    kernel=AcousticDoubleLayer(k)

    matrix=assembleMatrix(mToB,kernel,quadRule=quadrule)
    identity=assembleIdentity(mToB,quadrule)


    rhs=projRhs(mToB,[lambda t,x,normals: -numpy.exp(1j*k*x[1])],quadrule)
    coeffs=numpy.linalg.solve(.5*identity+matrix,rhs)
    

    gx,gy=numpy.mgrid[-2:4:200j,-2:2:200j]
    points=numpy.array([gx.ravel(),gy.ravel()])
    res=evaluate(points,mToB,kernel,quadrule,coeffs)
开发者ID:tbetcke,项目名称:PyBEM2D,代码行数:33,代码来源:evaluation.py

示例2:

# 需要导入模块: from mesh import Mesh [as 别名]
# 或者: from mesh.Mesh import discretize [as 别名]
            return vec






if  __name__ == "__main__":

    from bases import ElementToBasis,Legendre
    from segments import Line,Arc
    from quadrules import GaussQuadrature
    from kernels import Identity,AcousticDoubleLayer, AcousticSingleLayer
    from mesh import Domain,Mesh

    circle=Arc(0,0,0,2*numpy.pi,1)
    d=Domain([circle])
    mesh=Mesh([d])
    mesh.discretize(100)
    quadrule=GaussQuadrature(4,2,0.15)
    mToB=Legendre.legendreBasis(mesh,0)
    kernel=AcousticSingleLayer(1)
    matrix=assembleMatrix(mToB,kernel,quadRule=quadrule)
    identity=assembleIdentity(mToB,quadrule)
    res=projRhs(mToB,[lambda t,x,normals: numpy.sin(x[0])],quadrule)
    
    #fig=plt.plot(numpy.abs(numpy.diag(identity)))

    print "Finished" 

开发者ID:tbetcke,项目名称:PyBEM2D,代码行数:31,代码来源:assembly.py

示例3: plotBndFun

# 需要导入模块: from mesh import Mesh [as 别名]
# 或者: from mesh.Mesh import discretize [as 别名]
    from bases import ElementToBasis,Legendre,NodalLin
    from segments import Line,Arc
    from quadrules import GaussQuadrature
    from kernels import Identity,AcousticDoubleLayer
    from mesh import Domain,Mesh
    from assembly import Assembly, nodalProjector
    from evaluation import Evaluator
    

    k=10
    circle=Arc(0,0,0,2*numpy.pi,.5)
    circle2=Arc(2,0,0,2*numpy.pi,.5)
    d=Domain([circle])
    d2=Domain([circle2])
    mesh=Mesh([d,d2])
    mesh.discretize(50)
    quadrule=GaussQuadrature(5,3,0.15)
    #mToB=Legendre.legendreBasis(mesh,0)
    mToB=NodalLin.nodalLinBasis(mesh)
    kernel=AcousticDoubleLayer(k)

    assembly=Assembly(mToB,quadrule)
    mKernel=assembly.getKernel(kernel)
    mIdentity=assembly.getIdentity()
    op=mIdentity+2*mKernel
    rhs=assembly.projFun([lambda t,x,normals: -numpy.exp(1j*k*x[0])])

    coeffs=numpy.linalg.solve(.5*mIdentity+mKernel,rhs)
    plotBndFun(mToB,coeffs[:,0])
    ev=Evaluator(mToB,kernel,quadrule)
    v=Visualizer(ev,[-1.5,3.5,-1,3],100,100,incWave=lambda x: numpy.exp(1j*k*x[0]))
开发者ID:tbetcke,项目名称:PyBEM2D,代码行数:33,代码来源:visualization.py


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