本文整理汇总了Python中matplotlib.path.Path.codes方法的典型用法代码示例。如果您正苦于以下问题：Python Path.codes方法的具体用法？Python Path.codes怎么用？Python Path.codes使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类matplotlib.path.Path的用法示例。
在下文中一共展示了Path.codes方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: transform_path
# 需要导入模块: from matplotlib.path import Path [as 别名]
# 或者: from matplotlib.path.Path import codes [as 别名]
def transform_path(self, path):
vertices = path.vertices
# Intelligent interpolation needed
# ipath = path.interpolated(self._resolution)
ipath = path
ipath = path.interpolated(10)
# ipath = path.interpolated(3050)
verts = self.transform_no_mod(ipath.vertices)
codes = ipath.codes
# print verts.shape
# print 'transforming lon range:', np.min(verts[:, 0]), np.max(verts[:, 0])
# if np.isnan(np.max(verts[:, 0])):
# print 'Got nan: ', path, verts
paths = []
paths.append(Path(verts, codes))
# # Have any of the points wrapped? If so, pick up the pen, and start from -360
# if any(ipath.vertices[:, 0] > np.pi):
# v = ipath.vertices.copy()
# print 'splitting -:'
# v[:, 0] -= 2 * np.pi
# print v
# v = self.transform_no_mod(v)
# paths.append(Path(v))
#
# # Have any of the points wrapped? If so, pick up the pen, and start from +360
# if any(ipath.vertices[:, 0] < -np.pi):
# v = ipath.vertices.copy()
# v[:, 0] += 2 * np.pi
# print 'splitting +:'
# v = self.transform_no_mod(v)
# paths.append(Path(v))
s_pole = np.deg2rad(np.array([0, -89.9999]))
if path.contains_point(s_pole):
print 'POLE ALERT!!!', path
path = Path(verts[:-31])
paths = [path]
if len(paths) == 1:
path = paths[0]
else:
for path in paths:
if path.codes is not None:
if path.codes[0] == Path.MOVETO and all(path.codes[1:] == Path.LINETO):
path.codes = None
else:
# This is a bit strict... but a condition of make_compound_path
raise ValueError('Cannot draw discontiguous polygons.')
# print path.codes
path = Path.make_compound_path(*paths)
return path