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Python Database.fetch_website方法代码示例

本文整理汇总了Python中db.Database.fetch_website方法的典型用法代码示例。如果您正苦于以下问题:Python Database.fetch_website方法的具体用法?Python Database.fetch_website怎么用?Python Database.fetch_website使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在db.Database的用法示例。


在下文中一共展示了Database.fetch_website方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: get_results

# 需要导入模块: from db import Database [as 别名]
# 或者: from db.Database import fetch_website [as 别名]
def get_results(website_id):
    response = {}
    try:
        res_code = None;
        if not Database.website_exists(id=website_id):
            response['error'] = 'No Such Job Found'
            res_code = 202
        else:
            website = Database.fetch_website(id=website_id)
            response = website
            res_code = 200
        return  make_response(jsonify(response),res_code)
    except Exception as e:
        response['error']= 'Internal Error, Please Try Again.'
        return make_response(jsonify(response), 202)
开发者ID:KodeKracker,项目名称:Rotto-Links-Scraper,代码行数:17,代码来源:app.py

示例2: send_mail_to_user

# 需要导入模块: from db import Database [as 别名]
# 或者: from db.Database import fetch_website [as 别名]
def send_mail_to_user(website):
    """
    Sends email to user
    """
    try:
        # Create message container - the correct MIME type is
        # multipart/alternative.
        msg = MIMEMultipart('alternative')

        # Add user Mail ID to TO list
        website = Database.fetch_website(id=website.id)
        TO = [str(website['user']['email_id'])]

        msg['Subject'] = 'Crawler Result'
        msg['From'] = FROM
        msg['To'] = ','.join(TO)

        # Create the body of the message (an HTML version).
        mytemplate = Template(filename='rottoscraper/scraper/mail-template.html')
        # Pass result ID to template
        html = mytemplate.render(website_id=website['id'])

        # Record the MIME types of text/html.
        part = MIMEText(html, 'html')

        # Attach part into message container.
        msg.attach(part)

        # Set SMTP server login ceredentials and send mail
        server = smtplib.SMTP('smtp.sendgrid.net')
        server.starttls()
        server.login(SMTP_USER, SMTP_PASSWORD)
        server.sendmail(FROM, TO, msg.as_string())
        server.quit()
        log.info('Successfully sent the mail')
    except Exception as e:
        log.exception('Error in sending email to user')
开发者ID:KodeKracker,项目名称:Rotto-Links-Scraper,代码行数:39,代码来源:tasks.py


注:本文中的db.Database.fetch_website方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。