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Python Pen.arc_right方法代码示例

本文整理汇总了Python中canoepaddle.Pen.arc_right方法的典型用法代码示例。如果您正苦于以下问题:Python Pen.arc_right方法的具体用法?Python Pen.arc_right怎么用?Python Pen.arc_right使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在canoepaddle.Pen的用法示例。


在下文中一共展示了Pen.arc_right方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的Python代码示例。

示例1: test_arc_segment_bounds

# 需要导入模块: from canoepaddle import Pen [as 别名]
# 或者: from canoepaddle.Pen import arc_right [as 别名]
def test_arc_segment_bounds():
    # Arc which occupies its entire circle.
    p = Pen()
    p.fill_mode()
    p.move_to((1, 0))
    p.turn_to(90)
    p.arc_left(359, 1)

    arc = p.last_segment()
    assert_equal(
        arc.bounds(),
        Bounds(-1, -1, 1, 1)
    )

    # Arc which pushes the boundary only with the endpoints.
    p = Pen()
    p.fill_mode()
    p.move_to((0, 0))
    p.turn_to(30)
    p.move_forward(1)
    p.turn_left(90)
    p.arc_left(30, center=(0, 0))

    arc = p.last_segment()
    assert_equal(
        arc.bounds(),
        Bounds(0.5, 0.5, sqrt3 / 2, sqrt3 / 2)
    )

    # Arc which pushes the boundary with the middle in one spot.
    p = Pen()
    p.fill_mode()
    p.move_to((0, 0))
    p.turn_to(-45)
    p.move_forward(1)
    p.turn_left(90)
    p.arc_left(90, center=(0, 0))

    arc = p.last_segment()
    assert_equal(
        arc.bounds(),
        Bounds(sqrt2 / 2, -sqrt2 / 2, 1, sqrt2 / 2)
    )

    # Arc which goes right.
    p = Pen()
    p.fill_mode()
    p.move_to((0, 0))
    p.turn_to(45)
    p.arc_right(90, 3)

    arc = p.last_segment()
    assert_equal(
        arc.bounds(),
        Bounds(0, 0, 3 * sqrt2, 3 - 1.5 * sqrt2)
    )

    # Arc which pushes the boundary with the middle in two spots.
    p = Pen()
    p.fill_mode()
    p.move_to((0, 0))
    p.turn_to(-45)
    p.move_forward(1)
    p.turn_left(90)
    p.arc_left(180, center=(0, 0))

    arc = p.last_segment()
    assert_equal(
        arc.bounds(),
        Bounds(-sqrt2 / 2, -sqrt2 / 2, 1, 1)
    )

    # Half circle, right side
    p = Pen()
    p.fill_mode()
    p.move_to((0, 0))
    p.turn_to(0)
    p.arc_right(180, 5)

    arc = p.last_segment()
    assert_equal(
        arc.bounds(),
        Bounds(0, -10, 5, 0)
    )

    # Thick circle,
    p = Pen()
    p.stroke_mode(1.0)
    p.move_to((0, 0))
    p.turn_to(0)
    p.move_forward(5)
    p.turn_left(90)
    p.arc_left(180, 5, start_slant=45)

    arc = p.last_segment()
    assert_equal(
        arc.bounds(),
        Bounds(-5.5, -0.5314980314970469, 5.5, 5.5)
    )
开发者ID:christian-oudard,项目名称:canoepaddle,代码行数:101,代码来源:test_bounds.py

示例2: return

# 需要导入模块: from canoepaddle import Pen [as 别名]
# 或者: from canoepaddle.Pen import arc_right [as 别名]
    a = 12
    b = 0.03
    c = 0.2
    d = 1.5
    e = 0.5
    wobble = a * math.exp(-b * n) * math.sin(c * n + d * n**e)
    return (
        Angle(-24 + wobble),
        Angle(24 + wobble),
    )

center_heading = Heading(90)
center = p.position

p.turn_to(center_heading)

num_layers = 26
for layer in range(num_layers):
    lo, hi = f(layer)
    lo = center_heading + lo
    hi = center_heading + hi

    p.arc_right((p.heading - lo) + 90, center=center)
    p.arc_left(180, 1)

    p.arc_left((hi - p.heading) + 90, center=center)
    if layer < (num_layers - 1):
        p.arc_right(180, 1)

print(p.paper.format_svg(resolution=720 / p.paper.bounds().width))
开发者ID:christian-oudard,项目名称:canoepaddle,代码行数:32,代码来源:spaghetti.py


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