本文整理汇总了Python中Parser.Parser.output方法的典型用法代码示例。如果您正苦于以下问题：Python Parser.output方法的具体用法？Python Parser.output怎么用？Python Parser.output使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Parser.Parser的用法示例。
在下文中一共展示了Parser.output方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Python代码示例。
示例1: Parser
# 需要导入模块: from Parser import Parser [as 别名]
# 或者: from Parser.Parser import output [as 别名]
#Author: Josh Wretlind
#Python Assignment #3
#Class: CSCI 410 - Elements of Computing Systems
#Written in: Python 2.7
import sys,string,os
from Parser import Parser
infile = sys.argv[1] # Sys.argv is the system argument list object
outfile = sys.argv[2]
parse = Parser(infile)
outfilecontents = ""
while parse.hasMoreCommands():
parse.advance()
outfilecontents += parse.output()
output = open(outfile, 'w')
output.write(outfilecontents)
parse.stats()
示例2: Parser
# 需要导入模块: from Parser import Parser [as 别名]
# 或者: from Parser.Parser import output [as 别名]
from Code import Code
from Symbol import Symbol
infile = sys.argv[1] # Sys.argv is the system argument list object
outfile = infile.replace(".asm", ".hack")
parse = Parser(infile)
outfilecontents = ""
code = Code()
sym = Symbol()
i = 0
numOfNonLabelSymbols = 0
while parse.hasMoreCommands():
parse.advance()
parse.output()
parse.stripwhitespace()
if len(parse.parsedline) != 0 and parse.parsedline != "\n" and parse.commandType() == 2:
if not sym.contains(parse.symbol()):
sym.addEntry(parse.symbol(), str(i))
if len(parse.parsedline) != 0 and parse.parsedline != "\n" and parse.commandType() != 2:
i += 1
parse = Parser(infile)
while parse.hasMoreCommands():
parse.advance()
parse.output()
parse.stripwhitespace()
if (
len(parse.parsedline) != 0
and parse.parsedline != "\n"