本文整理汇总了Java中org.apache.commons.math3.exception.util.LocalizedFormats.NORMALIZE_NAN属性的典型用法代码示例。如果您正苦于以下问题：Java LocalizedFormats.NORMALIZE_NAN属性的具体用法？Java LocalizedFormats.NORMALIZE_NAN怎么用？Java LocalizedFormats.NORMALIZE_NAN使用的例子？那么, 这里精选的属性代码示例或许可以为您提供帮助。您也可以进一步了解该属性所在类org.apache.commons.math3.exception.util.LocalizedFormats的用法示例。
在下文中一共展示了LocalizedFormats.NORMALIZE_NAN属性的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的Java代码示例。
示例1: normalizeArray
/**
* Normalizes an array to make it sum to a specified value.
* Returns the result of the transformation
* <pre>
* x |-> x * normalizedSum / sum
* </pre>
* applied to each non-NaN element x of the input array, where sum is the
* sum of the non-NaN entries in the input array.
* <p>
* Throws IllegalArgumentException if {@code normalizedSum} is infinite
* or NaN and ArithmeticException if the input array contains any infinite elements
* or sums to 0.
* <p>
* Ignores (i.e., copies unchanged to the output array) NaNs in the input array.
*
* @param values Input array to be normalized
* @param normalizedSum Target sum for the normalized array
* @return the normalized array.
* @throws MathArithmeticException if the input array contains infinite
* elements or sums to zero.
* @throws MathIllegalArgumentException if the target sum is infinite or {@code NaN}.
* @since 2.1
*/
public static double[] normalizeArray(double[] values, double normalizedSum)
throws MathIllegalArgumentException, MathArithmeticException {
if (Double.isInfinite(normalizedSum)) {
throw new MathIllegalArgumentException(LocalizedFormats.NORMALIZE_INFINITE);
}
if (Double.isNaN(normalizedSum)) {
throw new MathIllegalArgumentException(LocalizedFormats.NORMALIZE_NAN);
}
double sum = 0d;
final int len = values.length;
double[] out = new double[len];
for (int i = 0; i < len; i++) {
if (Double.isInfinite(values[i])) {
throw new MathIllegalArgumentException(LocalizedFormats.INFINITE_ARRAY_ELEMENT, values[i], i);
}
if (!Double.isNaN(values[i])) {
sum += values[i];
}
}
if (sum == 0) {
throw new MathArithmeticException(LocalizedFormats.ARRAY_SUMS_TO_ZERO);
}
for (int i = 0; i < len; i++) {
if (Double.isNaN(values[i])) {
out[i] = Double.NaN;
} else {
out[i] = values[i] * normalizedSum / sum;
}
}
return out;
}
示例2: normalizeArray
/**
* Normalizes an array to make it sum to a specified value.
* Returns the result of the transformation <pre>
* x |-> x * normalizedSum / sum
* </pre>
* applied to each non-NaN element x of the input array, where sum is the
* sum of the non-NaN entries in the input array.</p>
*
* <p>Throws IllegalArgumentException if {@code normalizedSum} is infinite
* or NaN and ArithmeticException if the input array contains any infinite elements
* or sums to 0.</p>
*
* <p>Ignores (i.e., copies unchanged to the output array) NaNs in the input array.</p>
*
* @param values Input array to be normalized
* @param normalizedSum Target sum for the normalized array
* @return the normalized array.
* @throws MathArithmeticException if the input array contains infinite
* elements or sums to zero.
* @throws MathIllegalArgumentException if the target sum is infinite or {@code NaN}.
* @since 2.1
*/
public static double[] normalizeArray(double[] values, double normalizedSum) {
if (Double.isInfinite(normalizedSum)) {
throw new MathIllegalArgumentException(LocalizedFormats.NORMALIZE_INFINITE);
}
if (Double.isNaN(normalizedSum)) {
throw new MathIllegalArgumentException(LocalizedFormats.NORMALIZE_NAN);
}
double sum = 0d;
final int len = values.length;
double[] out = new double[len];
for (int i = 0; i < len; i++) {
if (Double.isInfinite(values[i])) {
throw new MathIllegalArgumentException(LocalizedFormats.INFINITE_ARRAY_ELEMENT, values[i], i);
}
if (!Double.isNaN(values[i])) {
sum += values[i];
}
}
if (sum == 0) {
throw new MathArithmeticException(LocalizedFormats.ARRAY_SUMS_TO_ZERO);
}
for (int i = 0; i < len; i++) {
if (Double.isNaN(values[i])) {
out[i] = Double.NaN;
} else {
out[i] = values[i] * normalizedSum / sum;
}
}
return out;
}