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C# Point.Distance方法代码示例

本文整理汇总了C#中System.Point.Distance方法的典型用法代码示例。如果您正苦于以下问题:C# Point.Distance方法的具体用法?C# Point.Distance怎么用?C# Point.Distance使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在System.Point的用法示例。


在下文中一共展示了Point.Distance方法的8个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。

示例1: IsDoubleClick

        /// <summary>
        /// Determines whether the last click is a double click.
        /// </summary>
        /// <param name="sender">The sender.</param>
        /// <param name="position">The position.</param>
        /// <returns>True if the click was a double click.</returns>
        internal static bool IsDoubleClick(object sender, Point position)
        {
            long clickTicks = DateTime.Now.Ticks;
            long elapsedTicks = clickTicks - lastClickTicks;
            long elapsedTime = elapsedTicks / TimeSpan.TicksPerMillisecond;
            bool quickClick = elapsedTime <= DoubleClickSpeed;
            bool senderMatch = lastSender != null && sender.Equals(lastSender.Target);

            if (senderMatch && quickClick && position.Distance(lastPosition) <= MaxMoveDistance)
            {
                // Double click!
                lastClickTicks = 0;
                lastSender = null;
                return true;
            }

            // Not a double click
            lastClickTicks = clickTicks;
            lastPosition = position;
            if (!quickClick)
            {
                lastSender = new WeakReference(sender);
            }

            return false;
        }
开发者ID:huoxudong125,项目名称:oxyplot,代码行数:32,代码来源:MouseButtonHelper.cs

示例2: ClosestPoint

 /// <summary>
 ///     Computes the closest point on this line segment to another point.
 /// </summary>
 /// <returns>
 ///     A Coordinate which is the closest point on the line segment to the point p.
 /// </returns>
 public static Point ClosestPoint(Point p, Point lineSegFrom, Point lineSegTo)
 {
     var factor = ProjectionFactor(p, lineSegFrom, lineSegTo);
     if ((factor > 0) && (factor < 1))
         return Project(p, lineSegFrom, lineSegTo);
     var dist0 = lineSegFrom.Distance(p);
     var dist1 = lineSegTo.Distance(p);
     return dist0 < dist1 ? lineSegFrom : lineSegTo;
 }
开发者ID:pauldendulk,项目名称:Mapsui,代码行数:15,代码来源:CGAlgoritm.cs

示例3: ClosestPoint

 /// <summary> 
 /// Computes the closest point on this line segment to another point.
 /// </summary>
 /// <param name="p">The point to find the closest point to.</param>
 /// <returns>
 /// A Coordinate which is the closest point on the line segment to the point p.
 /// </returns>
 public static Point ClosestPoint(Point p, Point LineSegFrom, Point LineSegTo)
 {
     var factor = ProjectionFactor(p, LineSegFrom, LineSegTo);
         if (factor > 0 && factor < 1)
             return Project(p, LineSegFrom, LineSegTo);
         var dist0 = LineSegFrom.Distance(p);
         var dist1 = LineSegTo.Distance(p);
         return dist0 < dist1 ? LineSegFrom : LineSegTo;
 }
开发者ID:PedroMaitan,项目名称:sharpmap,代码行数:16,代码来源:CGAlgoritm.cs

示例4: CheckVictory

        /// <summary>
        /// Checks if one of the players won
        /// </summary>
        /// <returns>playerId if someone won, -1 if no one did</returns>
        public string CheckVictory(int x, int y, int z)
        {
            /*
             * Basic winner finding algo:
             *  1. generate all posible direction vectors ([-1,-1,-1], [-1,-1,0] ... )
             *  2. move from current position in vector direction while its posible, getting point A
             *  3. move from current position in reverse vector direction while posible, getting point B
             *  4. if distance between A and B is field size, we've got the winner!
             *
             */
            var who = Field[x, y, z];
            if (who == 0) return null;
            var ways = new[] { -1, 0, 1 };
            foreach (var wx in ways)
            {
                foreach (var wy in ways)
                {
                    foreach (var wz in ways)
                    {
                        if (wx == 0 && wy == 0 && wz == 0)
                            continue;

                        Point pa = new Point(x, y, z);

                        Point pb = new Point(x, y, z);

                        Point newA;
                        while ((newA = pa.Move(wx, wy, wz, _fieldSize)) != null
                               && Field[newA.X, newA.Y, newA.Z] == who)
                        {
                            pa = newA;
                        }

                        Point newB;
                        while ((newB = pb.Move(-wx, -wy, -wz, _fieldSize)) != null
                               && Field[newB.X, newB.Y, newB.Z] == who)
                        {
                            pb = newB;
                        }

                        if (pa.Distance(pb) == _fieldSize)
                        {
                            return Players[who - 1];
                        }

                    }
                }
            }
            return null;
        }
开发者ID:pakrym,项目名称:tripplet,代码行数:54,代码来源:Game.cs

示例5: GetShortestPath

        public List<Node> GetShortestPath(Point startPoint, Point endPoint)
        {
            if (startPoint == null || endPoint == null)
                return null;

            // We create and place the start a goal node into the graph
            Node startNode = new Node(startPoint);
            Node endNode = new Node(endPoint);

            List<Node> path = null;

            if (false && startPoint.Distance(endPoint) > _cacheAcceptanceDistance)
            {

                // Check to see if this path is cached
                List<Node> cachedPath = GetCachedPath(startPoint, endPoint);
                if (cachedPath != null)
                {
                    // We have a close match, build the shortest path using the cached path
                    path = DStarLite(startNode, endNode, cachedPath);
                }
                else
                {
                    // No close match, use A*
                    path = AStar(startNode, endNode);
                }
            }
            else
            {
                // The points are close, just use A*
                path = AStar(startNode, endNode);
            }

            AddPathToShortestPathCache(path);

            // Return the path if there is one
            return (path != null && path.Contains(startNode))
                ? SmoothPath(path)
                : path;
        }
开发者ID:testing32,项目名称:AIProjects,代码行数:40,代码来源:Workspace.cs

示例6: DistancePointLine

        /// <summary>
        ///     Computes the distance from a point p to a line segment AB.
        ///     Note: NON-ROBUST!
        /// </summary>
        /// <param name="p">The point to compute the distance for.</param>
        /// <param name="a">One point of the line.</param>
        /// <param name="b">Another point of the line (must be different to A).</param>
        /// <returns> The distance from p to line segment AB.</returns>
        public static double DistancePointLine(Point p, Point a, Point b)
        {
            // if start == end, then use pt distance
            if (a.Equals(b))
                return p.Distance(a);

            // otherwise use comp.graphics.algorithms Frequently Asked Questions method
            /*(1)     	      AC dot AB
                        r =   ---------
                              ||AB||^2

                        r has the following meaning:
                        r=0 Point = A
                        r=1 Point = B
                        r<0 Point is on the backward extension of AB
                        r>1 Point is on the forward extension of AB
                        0<r<1 Point is interior to AB
            */

            var r = ((p.X - a.X)*(b.X - a.X) + (p.Y - a.Y)*(b.Y - a.Y))
                    /
                    ((b.X - a.X)*(b.X - a.X) + (b.Y - a.Y)*(b.Y - a.Y));

            if (r <= 0.0) return p.Distance(a);
            if (r >= 1.0) return p.Distance(b);

            /*(2)
                                                                (Ay-Cy)(Bx-Ax)-(Ax-Cx)(By-Ay)
                                                            s = -----------------------------
                                                                            Curve^2

                                                            Then the distance from C to Point = |s|*Curve.
                                                */

            var s = ((a.Y - p.Y)*(b.X - a.X) - (a.X - p.X)*(b.Y - a.Y))
                    /
                    ((b.X - a.X)*(b.X - a.X) + (b.Y - a.Y)*(b.Y - a.Y));

            return Math.Abs(s)*Math.Sqrt((b.X - a.X)*(b.X - a.X) + (b.Y - a.Y)*(b.Y - a.Y));
        }
开发者ID:pauldendulk,项目名称:Mapsui,代码行数:48,代码来源:CGAlgoritm.cs

示例7: Line

         public Line(Point beg, Point end) { 
             double l = beg.Distance(end);
             if (FP.eq(l, Math.PI)) {
                 Debug.Assert(FP.eq(beg.ra, end.ra));
                 phi = -Math.PI/2;
                 theta = Math.PI/2;
                 psi = beg.ra < 0.0 ? Math.PI*2 + beg.ra : beg.ra;
                 length = Math.PI;
                 return;
             }
             if (beg.Equals(end)) { 
                 phi    = Math.PI/2;
                 theta  = beg.dec;
                 psi    = beg.ra - Math.PI/2;
                 length = 0.0;
             } else { 
                 Point3D beg3d = new Point3D(beg);
                 Point3D end3d = new Point3D(end);
                 Point3D tp = new Point3D();
                 Point spt = beg3d.cross(end3d).toSpherePoint();
                 Euler euler = new Euler();
                 euler.phi     = - spt.ra - Math.PI/2;
                 euler.theta   =   spt.dec - Math.PI/2;
                 euler.psi     =   0.0 ;
                 euler.psi_a   = Euler.AXIS_Z;
                 euler.theta_a = Euler.AXIS_X;
                 euler.phi_a   = Euler.AXIS_Z;
                 euler.transform(tp, beg3d);
                 spt = tp.toSpherePoint();
 
                 // invert
                 phi = spt.ra;
                 theta = -euler.theta;
                 psi = -euler.phi;
                 length = l;
             }
         }
开发者ID:yan122725529,项目名称:TripRobot.Crawler,代码行数:37,代码来源:Sphere.cs

示例8: GetSelection

 public Selection GetSelection(Point point, double precision, bool inMotion = false)
 {
     if (point.Distance (Start) < precision) {
         return new Selection (this, SelectionPosition.LineStart);
     } else if (Points.Count == 2 && point.Distance (Stop) < precision) {
         return new Selection (this, SelectionPosition.LineStop);
     }
     return null;
 }
开发者ID:LongoMatch,项目名称:longomatch,代码行数:9,代码来源:PositionObject.cs


注:本文中的System.Point.Distance方法示例由纯净天空整理自Github/MSDocs等开源代码及文档管理平台,相关代码片段筛选自各路编程大神贡献的开源项目,源码版权归原作者所有,传播和使用请参考对应项目的License;未经允许,请勿转载。