本文整理汇总了C#中SyntaxNode.IsPartOfStructuredTrivia方法的典型用法代码示例。如果您正苦于以下问题:C# SyntaxNode.IsPartOfStructuredTrivia方法的具体用法?C# SyntaxNode.IsPartOfStructuredTrivia怎么用?C# SyntaxNode.IsPartOfStructuredTrivia使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类SyntaxNode
的用法示例。
在下文中一共展示了SyntaxNode.IsPartOfStructuredTrivia方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: GetAdjustedNodePosition
/// <summary>
/// A convenience method that determines a position from a node. If the node is missing,
/// then its position will be adjusted using CheckAndAdjustPosition.
/// </summary>
protected int GetAdjustedNodePosition(SyntaxNode node)
{
Debug.Assert(IsInTree(node));
var fullSpan = this.Root.FullSpan;
var position = node.SpanStart;
if (fullSpan.IsEmpty)
{
Debug.Assert(position == fullSpan.Start);
// At end of zero-width full span. No need to call
// CheckAndAdjustPosition since that will simply
// return the original position.
return position;
}
else if (position == fullSpan.End)
{
Debug.Assert(node.Width == 0);
// For zero-width node at the end of the full span,
// check and adjust the preceding position.
return CheckAndAdjustPosition(position - 1);
}
else if (node.IsMissing || node.HasErrors || node.Width == 0 || node.IsPartOfStructuredTrivia())
{
return CheckAndAdjustPosition(position);
}
else
{
// No need to adjust position.
return position;
}
}