本文整理汇总了C#中SyntaxNode.IsAnonymousFunction方法的典型用法代码示例。如果您正苦于以下问题:C# SyntaxNode.IsAnonymousFunction方法的具体用法?C# SyntaxNode.IsAnonymousFunction怎么用?C# SyntaxNode.IsAnonymousFunction使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类SyntaxNode
的用法示例。
在下文中一共展示了SyntaxNode.IsAnonymousFunction方法的5个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: BoundLambda
public BoundLambda(SyntaxNode syntax, BoundBlock body, ImmutableArray<Diagnostic> diagnostics, Binder binder, TypeSymbol delegateType, bool inferReturnType)
: this(syntax, (LambdaSymbol)binder.ContainingMemberOrLambda, body, diagnostics, binder, delegateType)
{
if (inferReturnType)
{
this._inferredReturnType = InferReturnType(
this.Body,
this.Binder,
delegateType,
this.Symbol.IsAsync,
ref this._inferredReturnTypeUseSiteDiagnostics,
out this._refKind,
out this._inferredFromSingleType);
#if DEBUG
_hasInferredReturnType = true;
#endif
}
Debug.Assert(
syntax.IsAnonymousFunction() || // lambda expressions
syntax is ExpressionSyntax && LambdaUtilities.IsLambdaBody(syntax, allowReducedLambdas: true) || // query lambdas
LambdaUtilities.IsQueryPairLambda(syntax) // "pair" lambdas in queries
);
}
示例2: GetLambdaEnclosingBinder
/// <summary>
/// Performs the same function as GetEnclosingBinder, but is known to take place within a
/// specified lambda. Walks up the syntax hierarchy until a node with an associated binder
/// is found.
/// </summary>
/// <remarks>
/// CONSIDER: can this share code with MemberSemanticModel.GetEnclosingBinder?
/// </remarks>
private Binder GetLambdaEnclosingBinder(int position, SyntaxNode startingNode, SyntaxNode containingLambda, ExecutableCodeBinder lambdaBinder)
{
AssertPositionAdjusted(position);
Debug.Assert(containingLambda.IsAnonymousFunction());
Debug.Assert(LookupPosition.IsInAnonymousFunctionOrQuery(position, containingLambda));
var current = startingNode;
while (current != containingLambda)
{
Debug.Assert(current != null);
StatementSyntax stmt = current as StatementSyntax;
if (stmt != null)
{
if (LookupPosition.IsInStatementScope(position, stmt))
{
Binder binder = lambdaBinder.GetBinder(current);
if (binder != null)
{
return binder;
}
}
}
else if (current.Kind == SyntaxKind.CatchClause)
{
if (LookupPosition.IsInCatchClauseScope(position, (CatchClauseSyntax)current))
{
Binder binder = lambdaBinder.GetBinder(current);
if (binder != null)
{
return binder;
}
}
}
else if (current.IsAnonymousFunction())
{
if (LookupPosition.IsInAnonymousFunctionOrQuery(position, current))
{
Binder binder = lambdaBinder.GetBinder(current);
if (binder != null)
{
return binder;
}
}
}
else
{
// If this ever breaks, make sure that all callers of
// CanHaveAssociatedLocalBinder are in sync.
Debug.Assert(!current.CanHaveAssociatedLocalBinder());
}
current = current.Parent;
}
return lambdaBinder;
}
示例3: GetBindableSyntaxNodeOfLambdaOrQuery
// We have a lambda; we want to find a syntax node or statement which can be bound such that
// we can get the type of the lambda, if there is one. For example if given
//
// A().B(x=>M(x)).C(); then we want to find A().B(x=>M())
// object d = (D)(x=>M(x)); then we want to find (D)(x=>M(x))
// D d = x=>M(x); then we want to find the whole thing.
//
protected virtual SyntaxNode GetBindableSyntaxNodeOfLambdaOrQuery(SyntaxNode node)
{
Debug.Assert(node != null);
Debug.Assert(node != this.Root);
Debug.Assert(node.IsAnonymousFunction() || node.IsQuery());
SyntaxNode current = node.Parent;
for (; current != this.Root; current = current.Parent)
{
Debug.Assert(current != null, "How did we get outside the root?");
if (current is StatementSyntax)
{
return current;
}
if (current.Kind == SyntaxKind.ParenthesizedExpression)
{
continue;
}
if (current is ExpressionSyntax)
{
return GetBindableSyntaxNode(current);
}
}
// We made it up to the root without finding a viable expression or statement. Just bind
// the lambda and hope for the best.
return node;
}
示例4: NodeIsExplicitType
private static bool NodeIsExplicitType(SyntaxNode node, SyntaxNode lambda)
{
Debug.Assert(node != null);
Debug.Assert(lambda != null);
Debug.Assert(lambda.IsAnonymousFunction() || lambda.IsQuery());
// UNDONE;
return false;
}
示例5: IsInAnonymousFunctionOrQuery
internal static bool IsInAnonymousFunctionOrQuery(int position, SyntaxNode lambdaExpressionOrQueryNode)
{
Debug.Assert(lambdaExpressionOrQueryNode.IsAnonymousFunction() || lambdaExpressionOrQueryNode.IsQuery());
SyntaxToken firstIncluded;
CSharpSyntaxNode body;
switch (lambdaExpressionOrQueryNode.Kind())
{
case SyntaxKind.SimpleLambdaExpression:
SimpleLambdaExpressionSyntax simple = (SimpleLambdaExpressionSyntax)lambdaExpressionOrQueryNode;
firstIncluded = simple.Parameter.Identifier;
body = simple.Body;
break;
case SyntaxKind.ParenthesizedLambdaExpression:
ParenthesizedLambdaExpressionSyntax parenthesized = (ParenthesizedLambdaExpressionSyntax)lambdaExpressionOrQueryNode;
firstIncluded = parenthesized.ParameterList.OpenParenToken;
body = parenthesized.Body;
break;
case SyntaxKind.AnonymousMethodExpression:
AnonymousMethodExpressionSyntax anon = (AnonymousMethodExpressionSyntax)lambdaExpressionOrQueryNode;
firstIncluded = anon.DelegateKeyword;
body = anon.Block;
break;
default:
// OK, so we have some kind of query clause. They all start with a keyword token, so we'll skip that.
firstIncluded = lambdaExpressionOrQueryNode.GetFirstToken().GetNextToken();
return IsBetweenTokens(position, firstIncluded, lambdaExpressionOrQueryNode.GetLastToken().GetNextToken());
}
var bodyStatement = body as StatementSyntax;
var firstExcluded = bodyStatement != null ?
GetFirstExcludedToken(bodyStatement) :
(SyntaxToken)SyntaxNavigator.Instance.GetNextToken(body, predicate: null, stepInto: null);
return IsBetweenTokens(position, firstIncluded, firstExcluded);
}