本文整理汇总了C#中SyntaxNode.DescendantTrivia方法的典型用法代码示例。如果您正苦于以下问题：C# SyntaxNode.DescendantTrivia方法的具体用法？C# SyntaxNode.DescendantTrivia怎么用？C# SyntaxNode.DescendantTrivia使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类SyntaxNode的用法示例。
在下文中一共展示了SyntaxNode.DescendantTrivia方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: PrintAllTrivia
/// <summary>
/// Print all the trivias.
/// </summary>
/// <param name="node"></param>
/// <returns></returns>
private string PrintAllTrivia(SyntaxNode node)
{
var trivias = node.DescendantTrivia();
var sb = new StringBuilder();
foreach (var trivia in trivias)
{
sb.AppendLine(trivia.Kind.ToString() + " " + trivia.GetText());
}
return sb.ToString();
}示例2: RemoveComments
private static SyntaxNode RemoveComments(SyntaxNode ele)
{
if (ele.HasLeadingTrivia)
{
var oldCommentsTrivias = from trivia in ele.GetLeadingTrivia().Where(
x => (x.Kind == SyntaxKind.MultiLineCommentTrivia || x.Kind == SyntaxKind.SingleLineCommentTrivia))
select trivia;
foreach (var comment in oldCommentsTrivias)
{
ele = ele.ReplaceTrivia(comment, SyntaxTriviaList.Empty);
}
}
if (ele.DescendantTrivia() != null && ele.DescendantTrivia().Count() > 0)
{
var containingComments = from trivia in ele.DescendantTrivia().Where(
x => (x.Kind == SyntaxKind.MultiLineCommentTrivia || x.Kind == SyntaxKind.SingleLineCommentTrivia))
select trivia;
foreach (var comment in containingComments)
{
ele = ele.ReplaceTrivia(comment, SyntaxTriviaList.Empty);
}
}
return ele;
}