本文整理汇总了C#中INode.IsSolid方法的典型用法代码示例。如果您正苦于以下问题:C# INode.IsSolid方法的具体用法?C# INode.IsSolid怎么用?C# INode.IsSolid使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类INode
的用法示例。
在下文中一共展示了INode.IsSolid方法的2个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C#代码示例。
示例1: ProcSubtree
private void ProcSubtree(float tx0, float ty0, float tz0, float tx1, float ty1, float tz1, INode node,
bool insideSolidNode, int currentDepth, int? wantedDepth,
Coords nodeCoords)
{
if (!_intersectMultiple && results.Count > 0) {
return;
}
if (tx1 < 0.0 || ty1 < 0.0 || tz1 < 0.0) {
return;
}
if (_debug) {
var entryDistance = Mathf.Max(tx0, ty0, tz0);
Debug.DrawLine(_ray.origin, _ray.GetPoint(entryDistance), Color.red, 0, false);
}
if (wantedDepth == null) {
if (node == null) {
return;
}
if (node.IsSolid()) {
ProcessTerminal(node, tx0, ty0, tz0);
if (results.Count > 0) {
return;
}
}
} else {
if (!insideSolidNode) {
//didn't manage to get into a solid node
if (node == null) {
return;
}
insideSolidNode = node.IsSolid();
}
if (insideSolidNode && currentDepth >= wantedDepth) {
if (currentDepth == wantedDepth) {
ProcessTerminal(nodeCoords, tx0, ty0, tz0);
} else {
//oops, went too deep!!!
//trace back to wanted depth
var newCoords = new OctreeChildCoords[wantedDepth.Value];
for (var i = 0; i < newCoords.Length; ++i) {
newCoords[i] = nodeCoords.GetCoord(i);
}
ProcessTerminal(new Coords(newCoords), tx0, ty0,
tz0);
}
if (results.Count > 0) {
return;
}
}
}
if (_debug) {
if (node != null) {
var bounds = node.GetBounds();
DrawBounds(bounds, Color.white);
} else {
//inside solid node and still going strong baby!
var bounds = _rootNode.GetChildBounds(nodeCoords);
DrawBounds(bounds, Color.cyan);
}
}
var txm = 0.5f * (tx0 + tx1);
var tym = 0.5f * (ty0 + ty1);
var tzm = 0.5f * (tz0 + tz1);
var currNode = FirstNode(tx0, ty0, tz0, txm, tym, tzm);
while (currNode < 8) {
var childIndex = (OctreeNode.ChildIndex) (currNode ^ _dimensionFlipFlags);
if (!_intersectMultiple && results.Count > 0) {
return;
}
var nextDepth = currentDepth + 1;
var childCoords = new Coords(nodeCoords,
OctreeChildCoords.FromIndex(childIndex));
INode childNode;
if (insideSolidNode) {
childNode = null;
} else {
childNode = node.GetChild(childIndex);
}
switch (currNode) {
//0= none
//1 = only x
//.........这里部分代码省略.........
示例2: RayIntersection
public RayIntersection(Transform transform, IOctree octree, Ray r, bool intersectMultiple, int? wantedDepth,
Filter filter, bool debug = false)
{
_filter = filter;
_debug = debug;
_tree = octree;
_rootNode = octree.GetRoot();
if (_rootNode == null) {
//we had a good run guys, time to call it a day
return;
}
_transform = transform;
_ray = r;
_intersectMultiple = intersectMultiple;
_dimensionFlipFlags = 0;
var rootBounds = _rootNode.GetBounds();
if (_debug) {
DrawBounds(rootBounds, Color.gray);
}
var rootCenter = rootBounds.center;
var ro = transform.InverseTransformPoint(r.origin) - rootCenter;
var rd = transform.InverseTransformDirection(r.direction);
var rox = ro.x;
var roy = ro.y;
var roz = ro.z;
var rdx = rd.x;
var rdy = rd.y;
var rdz = rd.z;
var ocMin = rootBounds.min - rootCenter;
var ocMax = rootBounds.max - rootCenter;
if (rdx < 0.0f) {
rox = -rox;
rdx = -rdx;
_dimensionFlipFlags |= 1;
}
if (rdy < 0.0f) {
roy = -roy;
rdy = -rdy;
_dimensionFlipFlags |= 2;
}
if (rdz < 0.0f) {
roz = -roz;
rdz = -rdz;
_dimensionFlipFlags |= 4;
}
float tx0, tx1, ty0, ty1, tz0, tz1;
if (!Mathf.Approximately(rdx, 0.0f)) {
tx0 = (ocMin.x - rox) / rdx;
tx1 = (ocMax.x - rox) / rdx;
} else {
tx0 = 99999.9f;
tx1 = 99999.9f;
}
if (!Mathf.Approximately(rdy, 0.0f)) {
ty0 = (ocMin.y - roy) / rdy;
ty1 = (ocMax.y - roy) / rdy;
} else {
ty0 = 99999.9f;
ty1 = 99999.9f;
}
if (!Mathf.Approximately(rdz, 0.0f)) {
tz0 = (ocMin.z - roz) / rdz;
tz1 = (ocMax.z - roz) / rdz;
} else {
tz0 = 99999.9f;
tz1 = 99999.9f;
}
if (_debug) {
Debug.DrawLine(_ray.origin, _ray.GetPoint(5000), Color.yellow);
}
if (Mathf.Max(tx0, ty0, tz0) < Mathf.Min(tx1, ty1, tz1)) {
ProcSubtree(tx0, ty0, tz0, tx1, ty1, tz1, _rootNode, _rootNode.IsSolid(), 0, wantedDepth,
_rootNode.GetCoords());
}
}