本文整理汇总了C++中btDynamicsWorld::removeRigidBody方法的典型用法代码示例。如果您正苦于以下问题：C++ btDynamicsWorld::removeRigidBody方法的具体用法？C++ btDynamicsWorld::removeRigidBody怎么用？C++ btDynamicsWorld::removeRigidBody使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类btDynamicsWorld的用法示例。
在下文中一共展示了btDynamicsWorld::removeRigidBody方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1:
virtual ~RigidObject()
{
if(body->getMotionState())
delete body->getMotionState();
world->removeRigidBody(body);
delete body;
}示例2:
virtual ~RigidObject()
{
if(body)
{
if(body->getMotionState() != NULL)
delete body->getMotionState();
// if(body->getCollisionShape() != NULL)
// delete body->getCollisionShape();
world->removeRigidBody(body);
delete body;
}
}示例3: clear
void FractureBody::clear(btDynamicsWorld& world)
{
for (int i = 0; i < m_connections.size(); ++i)
{
btRigidBody* cb = m_connections[i].m_body;
btAssert(!cb->getCollisionShape()->isCompound());
if (cb->isInWorld())
{
world.removeRigidBody(cb);
}
delete cb->getCollisionShape();
delete cb;
}
m_connections.clear();
}示例4:
virtual ~RagDoll ()
{
int i;
// Remove all constraints
for ( i = 0; i < JOINT_COUNT; ++i)
{
m_ownerWorld->removeConstraint(m_joints[i]);
delete m_joints[i]; m_joints[i] = 0;
}
// Remove all bodies and shapes
for ( i = 0; i < BODYPART_COUNT; ++i)
{
m_ownerWorld->removeRigidBody(m_bodies[i]);
delete m_bodies[i]->getMotionState();
delete m_bodies[i]; m_bodies[i] = 0;
delete m_shapes[i]; m_shapes[i] = 0;
}
}