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C++ board::findAllPossibleTurns方法代码示例

本文整理汇总了C++中board::findAllPossibleTurns方法的典型用法代码示例。如果您正苦于以下问题:C++ board::findAllPossibleTurns方法的具体用法?C++ board::findAllPossibleTurns怎么用?C++ board::findAllPossibleTurns使用的例子?那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在board的用法示例。


在下文中一共展示了board::findAllPossibleTurns方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: doTurn

board_turn agent_neural_statistical::doTurn ( board b, int player ) {

	/*

		This will be called when the agents needs to make a move.

		You are provided with
			-the board b: This is the current board state.
			-the int player: This is the player number of this agent on the board b.

		All your tiles on the board will have the contents of the int player.

		for all your tiles t, t.getContents ( ) = player.

		You cannot add on more arguments for this function.

	*/

	cout << "Player #" << player << "s turn, neural statistical agent.\n";

	b.print ( );

	auto originalBoard = b;
	int nRotations = b.rotateForPerspective ( player );

	board_turn t;

	vector < board_turn > possibleTurns = b.findAllPossibleTurns ( player );

	board_turn bestTurn = possibleTurns [ 0 ];
	double bestScore = 0;

	for ( size_t i = 0; i < possibleTurns.size ( ); ++ i ) {

		board b2 = b;
		b2.makeTurn ( possibleTurns [ i ] );

		vector < double > indata ( 121, 0 );
		for ( size_t i = 0; i < indata.size ( ); ++ i ) indata [ i ] = lib::intToIndata ( b.intToTile ( i ) -> getContents ( ), player );

		double score = nn.run ( indata ) [ 0 ];

		if ( bestScore < score ) {

			bestTurn = possibleTurns [ i ];
			bestScore = score;

		}

	}

	bestTurn.rotate ( 6 - nRotations );

	return bestTurn;

}
开发者ID:N00byEdge,项目名称:ChineseCheckersAI,代码行数:56,代码来源:agent_neural_statistical.cpp


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