本文整理汇总了C++中Mat::min方法的典型用法代码示例。如果您正苦于以下问题：C++ Mat::min方法的具体用法？C++ Mat::min怎么用？C++ Mat::min使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Mat的用法示例。
在下文中一共展示了Mat::min方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: eT
inline
void
interp1_helper_nearest(const Mat<eT>& XG, const Mat<eT>& YG, const Mat<eT>& XI, Mat<eT>& YI, const eT extrap_val)
{
arma_extra_debug_sigprint();
const eT XG_min = XG.min();
const eT XG_max = XG.max();
YI.copy_size(XI);
const eT* XG_mem = XG.memptr();
const eT* YG_mem = YG.memptr();
const eT* XI_mem = XI.memptr();
eT* YI_mem = YI.memptr();
const uword NG = XG.n_elem;
const uword NI = XI.n_elem;
uword best_j = 0;
for(uword i=0; i<NI; ++i)
{
eT best_err = Datum<eT>::inf;
const eT XI_val = XI_mem[i];
if((XI_val < XG_min) || (XI_val > XG_max))
{
YI_mem[i] = extrap_val;
}
else
{
// XG and XI are guaranteed to be sorted in ascending manner,
// so start searching XG from last known optimum position
for(uword j=best_j; j<NG; ++j)
{
const eT tmp = XG_mem[j] - XI_val;
const eT err = (tmp >= eT(0)) ? tmp : -tmp;
if(err >= best_err)
{
// error is going up, so we have found the optimum position
break;
}
else
{
best_err = err;
best_j = j; // remember the optimum position
}
}
YI_mem[i] = YG_mem[best_j];
}
}
}示例2: parse_matrices
void parse_matrices(string file, Mat<double> & M, Mat<double> & P0, Mat<double> & P1, Mat<int> & C, int nrows) {
ifstream ifs;
ifs.open(file.c_str());
if(!ifs.good()) {
cerr << "Error: couldn't open " << file << endl;
exit(1);
}
string str;
vector<string> tokens;
int m=-1,i=0;
int P0reducedcols=0;
int P1reducedcols=0;
while(true) {
bool spacer=false;
do {
if(!ifs.eof()) {
getline(ifs,str);
} else {
str="";
}
str=str.substr(0, str.find_first_of("#"));
tokens.clear();
tokenise(str, tokens, " ");
if(tokens.size() < 1) spacer=true;
} while(!ifs.eof() && tokens.size() < 1);
if(str.size()==0 && ifs.eof()) break;
if(spacer) {
m++;
i=0;
}
if(m==-1) m=0;
if(m==0) M.resize(nrows,tokens.size());
if(m==1) C.resize(nrows,tokens.size());
if(m==2) P0.resize(nrows,tokens.size());
if(m==3) P1.resize(nrows,tokens.size());
if(i >= nrows) {
cerr << "Error: number of rows of matrices greater than number of samples.\n";
exit(1);
}
for(int t=0; t < tokens.size(); t++) {
if(m==0) M(i,t) = atof(tokens[t].c_str());
if(m==1) C(i,t) = atoi(tokens[t].c_str());
if(m==2) {
for(int j=0; j < nrows; j++) {
if(i > max(C.col(0))) {
cerr << "Error: more distinct rows of P than classes for model 0 (" << i << " > " << max(C.col(0)) << ").\n";
exit(1);
}
if(C(j,0)==i) {
P0(j,t)= atof(tokens[t].c_str());
}
}
P0reducedcols = max(P0reducedcols, i);
}
if(m==3) {
for(int j=0; j < nrows; j++) {
if(i > max(C.col(1))) {
cerr << "Error: more distinct rows of P than classes for model 1 (" << i << " > " << max(C.col(1)) << ").\n";
exit(1);
}
if(C(j,1)==i) {
P1(j,t)= atof(tokens[t].c_str());
}
}
P1reducedcols = max(P1reducedcols, i);
}
}
i++;
}
if(C.min() != 0) {
cerr << "Error: need at least one class in each model labelled 0." << endl;
exit(1);
}
if(max(C.col(0)) != P0reducedcols) {
cerr << "Error: number of classes does not correspond to number of disinct rows of P for model 0.\n";
exit(1);
}
if(max(C.col(1)) != P1reducedcols) {
cerr << "Error: number of classes does not correspond to number of disinct rows of P for model 1.\n";
exit(1);
}
}