本文整理汇总了C++中LayoutBlock::firstChild方法的典型用法代码示例。如果您正苦于以下问题：C++ LayoutBlock::firstChild方法的具体用法？C++ LayoutBlock::firstChild怎么用？C++ LayoutBlock::firstChild使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类LayoutBlock的用法示例。
在下文中一共展示了LayoutBlock::firstChild方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: removeChild
void LayoutRubyRun::removeChild(LayoutObject* child)
{
// If the child is a ruby text, then merge the ruby base with the base of
// the right sibling run, if possible.
if (!beingDestroyed() && !documentBeingDestroyed() && child->isRubyText()) {
LayoutRubyBase* base = rubyBase();
LayoutObject* rightNeighbour = nextSibling();
if (base && rightNeighbour && rightNeighbour->isRubyRun()) {
// Ruby run without a base can happen only at the first run.
LayoutRubyRun* rightRun = toLayoutRubyRun(rightNeighbour);
if (rightRun->hasRubyBase()) {
LayoutRubyBase* rightBase = rightRun->rubyBaseSafe();
// Collect all children in a single base, then swap the bases.
rightBase->moveChildren(base);
moveChildTo(rightRun, base);
rightRun->moveChildTo(this, rightBase);
// The now empty ruby base will be removed below.
ASSERT(!rubyBase()->firstChild());
}
}
}
LayoutBlockFlow::removeChild(child);
if (!beingDestroyed() && !documentBeingDestroyed()) {
// Check if our base (if any) is now empty. If so, destroy it.
LayoutBlock* base = rubyBase();
if (base && !base->firstChild()) {
LayoutBlockFlow::removeChild(base);
base->deleteLineBoxTree();
base->destroy();
}
// If any of the above leaves the run empty, destroy it as well.
if (!hasRubyText() && !hasRubyBase()) {
deleteLineBoxTree();
destroy();
}
}
}示例2: needsSubtreeRecorder
// We need to balance the benefit of subtree optimization and the cost of subtree display items.
// Only output subtree information if the block has multiple children or multiple line boxes.
static bool needsSubtreeRecorder(const LayoutBlock& layoutBlock)
{
return (layoutBlock.firstChild() && layoutBlock.firstChild()->nextSibling())
|| (layoutBlock.isLayoutBlockFlow() && toLayoutBlockFlow(layoutBlock).firstLineBox() && toLayoutBlockFlow(layoutBlock).firstLineBox()->nextLineBox());
}