本文整理汇总了C++中LayerPtr::checkVisibility方法的典型用法代码示例。如果您正苦于以下问题：C++ LayerPtr::checkVisibility方法的具体用法？C++ LayerPtr::checkVisibility怎么用？C++ LayerPtr::checkVisibility使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类LayerPtr的用法示例。
在下文中一共展示了LayerPtr::checkVisibility方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: process
void Node::process(const LayerPtr& currentLayer)
{
if (children.empty())
{
if (currentLayer->checkVisibility(std::static_pointer_cast<Node>(shared_from_this())))
{
currentLayer->addToDrawQueue(std::static_pointer_cast<Node>(shared_from_this()));
}
}
else
{
std::stable_sort(children.begin(), children.end(), [](const NodePtr& a, const NodePtr& b) {
return a->getZ() > b->getZ();
});
auto i = children.begin();
NodePtr node;
for (; i != children.end(); ++i)
{
node = *i;
if (node->getZ() < 0.0f)
{
if (!node->isGlobalOrder() && node->isVisible() && currentLayer->checkVisibility(node))
{
currentLayer->addToDrawQueue(node);
}
}
else
{
break;
}
}
if (currentLayer->checkVisibility(std::static_pointer_cast<Node>(shared_from_this())))
{
currentLayer->addToDrawQueue(std::static_pointer_cast<Node>(shared_from_this()));
}
for (; i != children.end(); ++i)
{
node = *i;
if (!node->isGlobalOrder() && node->isVisible() && currentLayer->checkVisibility(node))
{
currentLayer->addToDrawQueue(node);
}
}
}
}