本文整理汇总了C++中InlineFlowBox::logicalBottomVisualOverflow方法的典型用法代码示例。如果您正苦于以下问题：C++ InlineFlowBox::logicalBottomVisualOverflow方法的具体用法？C++ InlineFlowBox::logicalBottomVisualOverflow怎么用？C++ InlineFlowBox::logicalBottomVisualOverflow使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类InlineFlowBox的用法示例。
在下文中一共展示了InlineFlowBox::logicalBottomVisualOverflow方法的1个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: hitTest
bool LineBoxList::hitTest(LayoutBoxModelObject* renderer, HitTestResult& result, const HitTestLocation& locationInContainer, const LayoutPoint& accumulatedOffset, HitTestAction hitTestAction) const
{
if (hitTestAction != HitTestForeground)
return false;
ASSERT(renderer->isLayoutBlock() || (renderer->isLayoutInline() && renderer->hasLayer())); // The only way an inline could hit test like this is if it has a layer.
// If we have no lines then we have no work to do.
if (!firstLineBox())
return false;
LayoutPoint point = locationInContainer.point();
LayoutRect rect(firstLineBox()->isHorizontal() ?
IntRect(point.x(), point.y() - locationInContainer.topPadding(), 1, locationInContainer.topPadding() + locationInContainer.bottomPadding() + 1) :
IntRect(point.x() - locationInContainer.leftPadding(), point.y(), locationInContainer.rightPadding() + locationInContainer.leftPadding() + 1, 1));
if (!anyLineIntersectsRect(renderer, rect, accumulatedOffset))
return false;
// See if our root lines contain the point. If so, then we hit test
// them further. Note that boxes can easily overlap, so we can't make any assumptions
// based off positions of our first line box or our last line box.
for (InlineFlowBox* curr = lastLineBox(); curr; curr = curr->prevLineBox()) {
RootInlineBox& root = curr->root();
if (rangeIntersectsRect(renderer, curr->logicalTopVisualOverflow(root.lineTop()), curr->logicalBottomVisualOverflow(root.lineBottom()), rect, accumulatedOffset)) {
bool inside = curr->nodeAtPoint(result, locationInContainer, accumulatedOffset, root.lineTop(), root.lineBottom());
if (inside) {
renderer->updateHitTestResult(result, locationInContainer.point() - toLayoutSize(accumulatedOffset));
return true;
}
}
}
return false;
}