本文整理汇总了C++中GeoPoint::Direct方法的典型用法代码示例。如果您正苦于以下问题：C++ GeoPoint::Direct方法的具体用法？C++ GeoPoint::Direct怎么用？C++ GeoPoint::Direct使用的例子？那么恭喜您, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类GeoPoint的用法示例。
在下文中一共展示了GeoPoint::Direct方法的2个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1:
TaskRendererSector::TaskRendererSector(const GeoPoint& center, double radius, double start, double end) {
if(start != end) { // Empty Sector ?
const int start_bearing = std::ceil(start);
const int end_bearing = std::floor((end > start) ? end : end + 360);
_GeoPoints.reserve(3 + (end_bearing - start_bearing));
for (int i = start_bearing; i <= end_bearing; ++i) {
_GeoPoints.push_back(center.Direct(static_cast<double> (i), radius));
}
_GeoPoints.push_back(center.Direct(end, radius));
} else {
_GeoPoints.reserve(2);
}
_GeoPoints.push_back(center);
_GeoPoints.push_back(center.Direct(start, radius));
_bounds.minx = _bounds.maxx = center.longitude;
_bounds.miny = _bounds.maxy = center.latitude;
for (GeoPoint& Pt : _GeoPoints) {
_bounds.minx = std::min(Pt.longitude, _bounds.minx);
_bounds.maxx = std::max(Pt.longitude, _bounds.maxx);
_bounds.miny = std::min(Pt.latitude, _bounds.miny);
_bounds.maxy = std::max(Pt.latitude, _bounds.maxy);
}
}示例2:
TaskRendererLine::TaskRendererLine(const GeoPoint& center, double radius, double radial) {
_GeoPoints.reserve(3);
_GeoPoints.push_back(center.Direct(radial - 90, radius));
_GeoPoints.push_back(center);
_GeoPoints.push_back(center.Direct(radial + 90, radius));
_bounds.minx = _bounds.maxx = center.longitude;
_bounds.miny = _bounds.maxy = center.latitude;
for (GeoPoint& Pt : _GeoPoints) {
_bounds.minx = std::min(Pt.longitude, _bounds.minx);
_bounds.maxx = std::max(Pt.longitude, _bounds.maxx);
_bounds.miny = std::min(Pt.latitude, _bounds.miny);
_bounds.maxy = std::max(Pt.latitude, _bounds.maxy);
}
}