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C++ Constant::getValue方法代码示例

本文整理汇总了C++中Constant::getValue方法的典型用法代码示例。如果您正苦于以下问题:C++ Constant::getValue方法的具体用法?C++ Constant::getValue怎么用?C++ Constant::getValue使用的例子?那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在Constant的用法示例。


在下文中一共展示了Constant::getValue方法的1个代码示例,这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞,您的评价将有助于系统推荐出更棒的C++代码示例。

示例1: test_sub_expr

static void test_sub_expr() {
	char c_str[100] = "4 - x";
	total++;

	cout << "test_sub_expr:\t\t\t\t";

	Math_Parser *p = new Math_Parser(c_str);
	Expression *e = p->Parse_Expression();

	if (!dynamic_cast<Term_Expr *>(e)) {
		cout << "FAIL\r\n";
		delete p;
		delete e;
		return;
	}

	Term_Expr *t = dynamic_cast<Term_Expr *>(e);

	if (!dynamic_cast<Constant *>(t->LHS)) {
		cout << "FAIL\r\n";
		delete p;
		delete e;
		return;
	}

	Constant *c = dynamic_cast<Constant *>(t->LHS);

	if (c->getValue() != 4 || !dynamic_cast<Sub_Expr *>(t->RHS)) {
		cout << "FAIL\r\n";
		delete p;
		delete e;
		return;
	}

	Sub_Expr *m = dynamic_cast<Sub_Expr *>(t->RHS);

	if (!dynamic_cast<Term_Expr *>(m->RHS)) {
		cout << "FAIL\r\n";
		delete p;
		delete e;
		return;
	}

	t = dynamic_cast<Term_Expr *>(m->RHS);

	if (!dynamic_cast<Variable *>(t->LHS) || t->RHS != NULL) {
		cout << "FAIL\r\n";
		delete p;
		delete e;
		return;
	}

	Variable *v = dynamic_cast<Variable *>(t->LHS);

	if (v->toString() != "x") {
		cout << "FAIL\r\n";
		delete p;
		delete e;
		return;
	}

	if (e->toString() != "4 - x") {
		cout << "FAIL\r\n";
		delete p;
		delete e;
		return;
	}

	cout << "PASS\r\n";
	passed++;
	delete p;
	delete e;
	return;
}
开发者ID:RichardH92,项目名称:math-evaluator,代码行数:74,代码来源:test.cpp


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