本文整理汇总了C++中Any::set方法的典型用法代码示例。如果您正苦于以下问题：C++ Any::set方法的具体用法？C++ Any::set怎么用？C++ Any::set使用的例子？那么, 这里精选的方法代码示例或许可以为您提供帮助。您也可以进一步了解该方法所在类Any的用法示例。
在下文中一共展示了Any::set方法的4个代码示例，这些例子默认根据受欢迎程度排序。您可以为喜欢或者感觉有用的代码点赞，您的评价将有助于系统推荐出更棒的C++代码示例。
示例1: main
int main() {
BaseA ba;
BaseB bb;
DerivA da;
DerivB db;
Any any;
assert(!any.isSet());
any.set(ba);
assert(any.isSet());
assert(any.get<BaseA>() == &ba);
assert(any.get<BaseB>() == NULL);
assert(any.get<DerivA>() == NULL);
assert(any.get<DerivB>() == NULL);
any.clear();
assert(!any.isSet());
assert(any.get<BaseA>() == NULL);
assert(any.get<BaseB>() == NULL);
assert(any.get<DerivA>() == NULL);
assert(any.get<DerivB>() == NULL);
any = bb;
assert(any.isSet());
assert(any.get<BaseA>() == NULL);
assert(any.get<BaseB>() == &bb);
assert(any.get<DerivA>() == NULL);
assert(any.get<DerivB>() == NULL);
any = da;
assert(any.isSet());
assert(any.get<BaseA>() == NULL);
assert(any.get<BaseB>() == NULL);
assert(any.get<DerivA>() == &da);
assert(any.get<DerivB>() == NULL);
any = db;
assert(any.isSet());
assert(any.get<BaseA>() == NULL);
assert(any.get<BaseB>() == NULL);
assert(any.get<DerivA>() == NULL);
assert(any.get<DerivB>() == &db);
Any any2 = any;
assert(any.isSet());
assert(any.get<BaseA>() == NULL);
assert(any.get<BaseB>() == NULL);
assert(any.get<DerivA>() == NULL);
assert(any.get<DerivB>() == &db);
Any any3(any2);
assert(any.isSet());
assert(any.get<BaseA>() == NULL);
assert(any.get<BaseB>() == NULL);
assert(any.get<DerivA>() == NULL);
assert(any.get<DerivB>() == &db);
return 0;
}示例2: toAny
Any VisibleEntity::toAny() const {
Any a = Entity::toAny();
a.setName("VisibleEntity");
a.set("visible", m_visible);
// Model and pose must already have been set, so no need to change anything
return a;
}示例3: toAny
Any VisibleEntity::toAny(const bool forceAll) const {
Any a = Entity::toAny(forceAll);
a.setName("VisibleEntity");
AnyTableReader oldValues(a);
bool visible;
if (forceAll || (oldValues.getIfPresent("visible", visible) && visible != m_visible)) {
a.set("visible", m_visible);
}
// Model and pose must already have been set, so no need to change anything
return a;
}示例4: Any
static void testRefCount2() {
// Explicit allocation so that we can control destruction
Any* a = new Any(Any::TABLE);
// Put something complex the table, so that we have chains of dependencies
a->set("x", Any(Any::TABLE));
Any* b = new Any();
// Create alias
*b = *a;
// a->m_data->referenceCount.m_value should now be 2
delete b;
b = NULL;
// Reference count should now be 1
delete a;
a = NULL;
// Reference count should now be zero (and the object deallocated)
}