unordered_multimap::reserve()是C++ STL中的内置函数,该函数将容器中的存储桶数(bucket_count)设置为最合适的数字,以使其至少包含n个元素。如果n大于当前的bucket_count乘以max_load_factor,则该容器的bucket_count会增加,并强制进行重新哈希处理。通过使用unordered_multimap容器预期的大小调用reserve,可以避免多次重复。多次重复是由于容器大小增加而产生的,从而优化了哈希表的大小。如果n小于该值,则该函数可能无效。
用法:
unordered_multimap_name.reserve(N)
参数:该函数接受单个强制性参数N,该参数将请求的元素数指定为最小容量。
返回值:该函数不返回任何内容。
以下示例程序旨在说明上述函数:
示例1:
// C++ program to illustrate the
// unordered_multimap::reserve()
#include <bits/stdc++.h>
using namespace std;
int main()
{
// declaration
unordered_multimap<int, int> sample1, sample2;
// the sample1 size is reserved for
// the bucket to contain a minimum of
// one elements
sample1.reserve(1);
// inserts key and element
// in sample1
sample1.insert({ 10, 100 });
sample1.insert({ 50, 500 });
// inserts key and element
// in sample1
// the sample1 size is reserved for
// the bucket to contain a minimum of
// three elements
sample2.reserve(3);
sample2.insert({ 20, 200 });
sample2.insert({ 30, 300 });
sample2.insert({ 30, 150 });
cout << "The size of Sample1 is: " << sample1.size();
cout << "\nKey and Elements of Sample1 are:";
for (auto it = sample1.begin(); it != sample1.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
cout << "\n\nThe size of Sample2 is: " << sample2.size();
cout << "\nKey and Elements of Sample2 are:";
for (auto it = sample2.begin(); it != sample2.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
return 0;
}
输出:
The size of Sample1 is: 2 Key and Elements of Sample1 are:{50, 500} {10, 100} The size of Sample2 is: 3 Key and Elements of Sample2 are:{30, 150} {30, 300} {20, 200}
示例2:
// C++ program to illustrate the
// unordered_multimap::reserve()
#include <bits/stdc++.h>
using namespace std;
int main()
{
// declaration
unordered_multimap<char, char> sample1, sample2;
// the sample1 size is reserved for
// the bucket to contain a minimum of
// one elements
sample1.reserve(1);
// inserts key and element
// in sample1
sample1.insert({ 'a', 'A' });
sample1.insert({ 'g', 'G' });
// inserts key and element
// in sample1
// the sample1 size is reserved for
// the bucket to contain a minimum of
// three elements
sample2.reserve(3);
sample2.insert({ 'b', 'B' });
sample2.insert({ 'c', 'C' });
sample2.insert({ 'd', 'D' });
cout << "The size of Sample1 is: " << sample1.size();
cout << "\nKey and Elements of Sample1 are:";
for (auto it = sample1.begin(); it != sample1.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
cout << "\n\nThe size of Sample2 is: " << sample2.size();
cout << "\nKey and Elements of Sample2 are:";
for (auto it = sample2.begin(); it != sample2.end(); it++) {
cout << "{" << it->first << ", " << it->second << "} ";
}
return 0;
}
输出:
The size of Sample1 is: 2 Key and Elements of Sample1 are:{g, G} {a, A} The size of Sample2 is: 3 Key and Elements of Sample2 are:{d, D} {c, C} {b, B}
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注:本文由纯净天空筛选整理自gopaldave大神的英文原创作品 unordered_multimap reserve() function in C++ STL。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。