Subset.next_lexicographic():next_lexicographic()是一个sympy Python库函数,它返回下一个按字典顺序排序的子集。
用法:
sympy.combinatorics.subset.Subset.next_lexicographic()
返回:
下一个按字典顺序排序的子集
代码1:next_lexicographic()示例
# Python code explaining
# SymPy.Subset.next_lexicographic()
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset
# Using from
# sympy.combinatorics.subset.Subsets.next_lexicographic()
# Creating Subset
a = Subset(['c', 'd'], ['geek', 'for', 'c', 'd'])
# next_lexicographic value
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)
输出:
Subset a next_lexicographic : [‘d’]
代码2:next_lexicographic()示例
# Python code explaining
# SymPy.Subset.next_lexicographic()
# importing SymPy libraries
from sympy.combinatorics import Permutation, Cycle
from sympy.combinatorics.subsets import Subset
# Using from
# sympy.combinatorics.subset.Subsets.next_lexicographic()
# Creating Subset
a = Subset(['k', 'a'], ['23', 'k', 'a'])
# next_lexicographic value
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)
输出:
Subset a next_lexicographic : [‘a’]
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