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Python Sympy Subset.next_lexicographic()用法及代码示例


Subset.next_lexicographic():next_lexicographic()是一个sympy Python库函数,它返回下一个按字典顺序排序的子集。

用法:
sympy.combinatorics.subset.Subset.next_lexicographic()

返回:
下一个按字典顺序排序的子集


代码1:next_lexicographic()示例

# Python code explaining 
# SymPy.Subset.next_lexicographic() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.next_lexicographic() 
  
# Creating Subset 
a = Subset(['c', 'd'], ['geek', 'for', 'c', 'd']) 
  
# next_lexicographic value 
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)

输出:

Subset a next_lexicographic : [‘d’]

代码2:next_lexicographic()示例

# Python code explaining 
# SymPy.Subset.next_lexicographic() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.next_lexicographic() 
  
# Creating Subset 
a = Subset(['k', 'a'], ['23', 'k', 'a']) 
  
# next_lexicographic value 
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)

输出:

Subset a next_lexicographic : [‘a’]



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注:本文由纯净天空筛选整理自noobestars101大神的英文原创作品 SymPy | Subset.next_lexicographic() in Python。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。