Python Sympy Subset.next_lexicographic()用法及代碼示例

Subset.next_lexicographic()：next_lexicographic()是一個sympy Python庫函數，它返回下一個按字典順序排序的子集。

用法：

sympy.combinatorics.subset.Subset.next_lexicographic()

返回：
下一個按字典順序排序的子集

代碼1：next_lexicographic()示例

# Python code explaining 
# SymPy.Subset.next_lexicographic() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.next_lexicographic() 
  
# Creating Subset 
a = Subset(['c', 'd'], ['geek', 'for', 'c', 'd']) 
  
# next_lexicographic value 
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)

輸出：

Subset a next_lexicographic : [‘d’]

代碼2：next_lexicographic()示例

# Python code explaining 
# SymPy.Subset.next_lexicographic() 
  
# importing SymPy libraries 
from sympy.combinatorics import Permutation, Cycle 
from sympy.combinatorics.subsets import Subset 
  
# Using from  
# sympy.combinatorics.subset.Subsets.next_lexicographic() 
  
# Creating Subset 
a = Subset(['k', 'a'], ['23', 'k', 'a']) 
  
# next_lexicographic value 
print ("Subset a next_lexicographic : ", a.next_lexicographic().subset)

輸出：

Subset a next_lexicographic : [‘a’]

相關用法

注：本文由純淨天空篩選整理自noobestars101大神的英文原創作品 SymPy | Subset.next_lexicographic() in Python。非經特殊聲明，原始代碼版權歸原作者所有，本譯文未經允許或授權，請勿轉載或複製。