当前位置: 首页>>代码示例 >>用法及示例精选 >>正文


Python Sympy Permutation.is_Identity()用法及代码示例


Permutation.is_Identity():is_Identity()是一个sympy Python库函数,用于检查Permutation是否为标识置换。

用法: sympy.combinatorics.permutations.Permutation.is_Identity()

返回:true –如果“置换”是一个身份置换;否则为假


代码1:is_Identity()示例

# Python code explaining 
# SymPy.Permutation.is_Identity() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method  
  
# creating Permutation 
a = Permutation([[2, 0], [3, 1]]) 
  
b = Permutation([1, 3, 5, 4, 2, 0]) 
  
print ("Permutation a - is_Identity form : ", a.is_Identity) 
print ("Permutation b - is_Identity form : ", b.is_Identity)

输出:

Permutation a – is_Identity form : False
Permutation b – is_Identity form : False

代码2:is_Identity()示例– 2D排列

# Python code explaining 
# SymPy.Permutation.is_Identity() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method  
  
# creating Permutation 
a = Permutation([[2, 4, 0],  
                 [3, 1, 2], 
                 [1, 5, 6]]) 
  
  
print ("Permutation a - is_Identity form : ", a.is_Identity)

输出:

Permutation a – is_Identity form : False



相关用法


注:本文由纯净天空筛选整理自noobestars101大神的英文原创作品 SymPy | Permutation.is_Identity() in Python。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。