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Python Sympy Permutation.is_Identity()用法及代碼示例


Permutation.is_Identity():is_Identity()是一個sympy Python庫函數,用於檢查Permutation是否為標識置換。

用法: sympy.combinatorics.permutations.Permutation.is_Identity()

返回:true –如果“置換”是一個身份置換;否則為假


代碼1:is_Identity()示例

# Python code explaining 
# SymPy.Permutation.is_Identity() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method  
  
# creating Permutation 
a = Permutation([[2, 0], [3, 1]]) 
  
b = Permutation([1, 3, 5, 4, 2, 0]) 
  
print ("Permutation a - is_Identity form : ", a.is_Identity) 
print ("Permutation b - is_Identity form : ", b.is_Identity)

輸出:

Permutation a – is_Identity form : False
Permutation b – is_Identity form : False

代碼2:is_Identity()示例– 2D排列

# Python code explaining 
# SymPy.Permutation.is_Identity() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.is_Identity() method  
  
# creating Permutation 
a = Permutation([[2, 4, 0],  
                 [3, 1, 2], 
                 [1, 5, 6]]) 
  
  
print ("Permutation a - is_Identity form : ", a.is_Identity)

輸出:

Permutation a – is_Identity form : False



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注:本文由純淨天空篩選整理自noobestars101大神的英文原創作品 SymPy | Permutation.is_Identity() in Python。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。