bit_or是C++中的内置函数,用于执行bitwise_or并在对其参数应用bitwise_or操作后返回结果。
头文件:
#include <functional.h>
模板类别:
template <class T> struct bit_or;
参数:它接受参数T,它是函数调用要比较的参数的类型。
Note:
- 此类的对象可用于标准算法,例如变换或累加。
- 成员函数('operator()')返回其参数的bitwise_or。
我们必须包括库‘functional’和‘algorithm’才能分别使用bit_or和transform()。
下面是C++中bit_or的图示:
问题一:
// C++ program to show the
// functionality of bit_or
#include <algorithm> // to include transform
#include <functional> // to include bit_or
#include <iostream>
#include <iterator>
using namespace std;
int main()
{
// declaring the values
int xyz[] = { -7, 2, 5, 100, 1029 };
int abc[] = { -4, 0, 5, 1, 1 };
int n = 5;
// defining results
int results[n];
// transform is used to apply
// bitwise_or on the arguments
transform(xyz, end(xyz), abc,
results, bit_or<int>());
// printing the resulting array
cout << "Results:";
for (const int& x:results)
cout << ' ' << x;
return 0;
}
输出:
Results:-3 2 5 101 1029
Some points to Remember
- Bitwise_or of a number with zero results into the number itself.
- Bitwise_or of two same numbers is also equal to that number itself
- If the number is odd it’s bit_or with 1 will result into same number
- If the number is even it’s bit_or with 1 will always results into “number+1”
问题2:
// C++ program to show the
// functionality of bit_or
#include <algorithm>
#include <functional>
#include <iostream>
#include <iterator>
using namespace std;
int main()
{
// declaring the values
// in form of hexadecimals
int xyz[] = { 0, 1100 };
int abc[] = { 0xf, 0xf };
// defining results
int results[2];
// transform is used to apply
// bitwise_or on the arguments
transform(xyz, end(xyz), abc,
results, bit_or<int>());
// printing the resulting array
cout << "Results:";
for (const int& x:results)
cout << ' ' << x;
return 0;
}
输出:
Results:15 1103
参考: https://en.cppreference.com/w/cpp/utility/functional/bit_or
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注:本文由纯净天空筛选整理自karan_gandhi大神的英文原创作品 std::bit_or in C++ with Examples。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。