在 Scala Stack class
,则使用find()方法返回满足堆栈中给定谓词的元素。
函数定义: def find(p: (A) => Boolean): Option[A]
返回类型: It returns the first element that satisfies a given predicate if present or else it returns None.
范例1:
// Scala program of find()
// method
// Import Stack
import scala.collection.mutable._
// Creating object
object GfG
{
// Main method
def main(args:Array[String])
{
// Creating stack
val s1 = Stack(1, 3, 2, 7, 6, 5)
// Print the stack
println(s1)
// Applying find method
val result = s1.find(x => {x % 7 == 0})
// Display output
println("Element divisible by 7: " + result)
}
}
输出:
Stack(1, 3, 2, 7, 6, 5) Element divisible by 7: Some(7)
范例2:
// Scala program of find()
// method
// Import Stack
import scala.collection.mutable._
// Creating object
object GfG
{
// Main method
def main(args:Array[String])
{
// Creating stack
val s1 = Stack(1, 3, 2, 7, 6, 5)
// Print the stack
println(s1)
// Applying find method
val result = s1.find(x => {x % 10 == 0})
// Display output
println("Element divisible by 10: " + result)
}
}
输出:
Stack(1, 3, 2, 7, 6, 5) Element divisible by 10: None
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注:本文由纯净天空筛选整理自rupesh_rao大神的英文原创作品 Scala Stack find() method with example。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。