在 Scala Stack class
,則使用find()方法返回滿足堆棧中給定謂詞的元素。
函數定義: def find(p: (A) => Boolean): Option[A]
返回類型: It returns the first element that satisfies a given predicate if present or else it returns None.
範例1:
// Scala program of find()
// method
// Import Stack
import scala.collection.mutable._
// Creating object
object GfG
{
// Main method
def main(args:Array[String])
{
// Creating stack
val s1 = Stack(1, 3, 2, 7, 6, 5)
// Print the stack
println(s1)
// Applying find method
val result = s1.find(x => {x % 7 == 0})
// Display output
println("Element divisible by 7: " + result)
}
}
輸出:
Stack(1, 3, 2, 7, 6, 5) Element divisible by 7: Some(7)
範例2:
// Scala program of find()
// method
// Import Stack
import scala.collection.mutable._
// Creating object
object GfG
{
// Main method
def main(args:Array[String])
{
// Creating stack
val s1 = Stack(1, 3, 2, 7, 6, 5)
// Print the stack
println(s1)
// Applying find method
val result = s1.find(x => {x % 10 == 0})
// Display output
println("Element divisible by 10: " + result)
}
}
輸出:
Stack(1, 3, 2, 7, 6, 5) Element divisible by 10: None
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注:本文由純淨天空篩選整理自rupesh_rao大神的英文原創作品 Scala Stack find() method with example。非經特殊聲明,原始代碼版權歸原作者所有,本譯文未經允許或授權,請勿轉載或複製。