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Python SymPy Permutation.descents()用法及代码示例


Permutation.descents():descents()是一个sympy Python库函数,它返回排列中下降的位置。下降是a [i]> a [i + 1]的元素

用法: sympy.combinatorics.permutations.Permutation.descents()

返回:下降在排列中的位置


代码1:descents()示例

# Python code explaining 
# SymPy.descents() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.descents() method  
  
# creating Permutation 
a = Permutation([[2, 0], [3, 1]]) 
  
b = Permutation([1, 3, 5, 4, 2, 0]) 
  
  
print ("Permutation a - descents form : ", a.descents()) 
print ("Permutation b - descents form : ", b.descents())

输出:

Permutation a – descents form : [1]
Permutation b – descents form : [2, 3, 4]

代码2:descents()示例– 2D排列

# Python code explaining 
# SymPy.descents() 
  
# importing SymPy libraries 
from sympy.combinatorics.partitions import Partition 
from sympy.combinatorics.permutations import Permutation 
  
# Using from sympy.combinatorics.permutations.Permutation.descents() method  
  
# creating Permutation 
a = Permutation([[2, 4, 0],  
                 [3, 1, 2], 
                 [1, 5, 6]]) 
  
  
print ("Permutation a - descents form : ", a.descents())

输出:

Permutation a – descents form : [0, 3, 5]



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