Permutation.commutes_with():commutes_with()是一个sympy Python库函数,用于检查两个置换是否在交换。假设“ a”和“ b”是“ C”的一部分,则a和b的换向器是a和b上下班的“ C”标识,即ab == ba。
用法:
sympy.combinatorics.permutations.Permutation.commutes_with()
返回:
检查两个排列是否在换向
代码1:commutes_with()示例
# Python code explaining
# SymPy.Permutation.commutes_with()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.commutes_with() method
# creating Permutation
a = Permutation([2, 0, 3, 1, 5, 4])
b = Permutation([3, 1, 2, 5, 4, 0])
print ("Permutation a - commutes_with form : ", a.commutes_with(b))
print ("Permutation b - commutes_with form : ", b.commutes_with(a))
输出:
Permutation a – commutes_with form : False
Permutation b – commutes_with form : False
代码2:commutes_with()示例–自换向器
# Python code explaining
# SymPy.Permutation.commutes_with()
# importing SymPy libraries
from sympy.combinatorics.partitions import Partition
from sympy.combinatorics.permutations import Permutation
# Using from sympy.combinatorics.permutations.Permutation.commutes_with() method
# creating Permutation
a = Permutation([[2, 4, 0],
[3, 1, 2],
[1, 5, 6]])
# SELF COMMUTATING
print ("Permutation a - commutes_with form : ", a.commutes_with(a))
输出:
Permutation a – commutes_with form : True
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