modf()函数是Python中的内置函数,它返回two-item元组中数字的小数和整数部分。两个部分的符号与数字相同。整数部分以浮点数形式返回。
用法:
modf(number)
参数:
There is only one mandatory parameter which is the number.
返回值:
此方法返回two-item元组中数字的小数和整数部分。两个部分的符号与数字相同。整数部分以浮点数形式返回。
异常:
TypeError: If anything other then a float number is passed, it returns a type error.
下面是modf()方法的Python3实现:
代码#1
# Python3 program to demonstrate the function modf()
# This will import math module
import math
# modf() function used with a positive number
print("math.modf(100.12):", math.modf(100.12))
# modf() function used with a negative number
print("math.modf(-100.72):", math.modf(-100.72))
print("math.modf(2):", math.modf(2))
输出:
math.modf(100.12): (0.12000000000000455, 100.0) math.modf(-100.72): (-0.7199999999999989, -100.0) math.modf(2): (0.0, 2.0)
代码2:TypeError
# Python3 program to demonstrate the
# error in function modf()
# This will import math module
import math
# modf() function used with a positive number
print("math.modf(100.12):", math.modf("100.12"))
输出:
Traceback (most recent call last): File "/home/fa6d7643de17bafe9a0e0693458e4bdb.py", line 9, in print("math.modf(100.12):", math.modf("100.12")) TypeError:a float is required
代码#3:
# Python3 program to demonstrate the
# error in function modf()
# This will import math module
from math import modf
lst = [3.12, -5.14, 13.25, -5.21]
tpl = (33.12, -15.25, 3.15, -31.2)
# modf() function on elements of list
print("modf() on First list element:", modf(lst[0]))
print("modf() on third list element:", modf(lst[2]))
# modf() function on elements of tuple
print("modf() on Second tuple element:", modf(tpl[1]))
print("modf() on Fourth tuple element:", modf(tpl[3]))
输出:
modf() on First list element: (0.1200000000000001, 3.0) modf() on third list element: (0.25, 13.0) modf() on Second tuple element: (-0.25, -15.0) modf() on Fourth tuple element: (-0.1999999999999993, -31.0)
实际应用:
给定两个浮点数,将小数部分相乘并返回答案。
代码4:
# Python3 program to demonstrate the
# application of function modf()
# This will import math module
import math
# modf() function to multiply fractional part
a = math.modf(11.2)
b = math.modf(12.3)
# Multiply the fractional part as is stored
# in 0th index of both the tuple
print(a[0]*b[0])
输出:
0.05999999999999993
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