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Java PushbackReader skip(long)用法及代码示例


Java中的PushbackReader类的skip(long)方法用于跳过流中指定数量的字符。此字符数被指定为参数。如果通过跳过到达流的末尾,它将阻塞流,直到它获得一些字符或抛出IOException。

用法:

public long skip(long numberOfChar)

参数:此方法接受参数numberOfChar,该参数是此方法要跳过的字符数。


返回值:此方法返回一个long值,该值是此方法跳过的实际字符数。

异常:该方法抛出:

  • IOException:如果输入输出时发生一些错误
  • IllegalArgumentException:如果传递的numberOfChar为负。

下面的方法说明了skip(long)方法的用法方式:

示例1:

// Java program to demonstrate 
// PushbackReader skip(long) method 
  
import java.io.*; 
import java.util.*; 
  
class GFG { 
    public static void main(String[] args) 
    { 
  
        try { 
            // Initializing a StringReader 
            // and PushbackReader 
            String s = "GeeksForGeeks"; 
  
            StringReader stringReader 
                = new StringReader(s); 
            PushbackReader pushbackReader 
                = new PushbackReader(stringReader); 
  
            // Get the character 
            // to be read from the stream 
            int ch; 
  
            // Read the first 5 characters 
            // to this reader using read() method 
            // This will put the str in the stream 
            // till it is read by the reader 
            for (int i = 0; i < 5; i++) { 
                ch = pushbackReader.read(); 
                System.out.print((char)ch); 
            } 
  
            System.out.println(); 
  
            // skip 3 characters using skip(long) 
            pushbackReader.skip(3); 
  
            System.out.println("Next 3 characters skipped."); 
  
            // Read the 2 characters 
            // to this reader using read() method 
            for (int i = 0; i < 2; i++) { 
                ch = pushbackReader.read(); 
                System.out.print((char)ch); 
            } 
  
            System.out.println(); 
  
            // Close the stream 
            pushbackReader.close(); 
            System.out.println("Stream Closed."); 
        } 
        catch (Exception e) { 
            System.out.println(e); 
        } 
    } 
}
输出:
Geeks
Next 3 characters skipped.
Ge
Stream Closed.

示例2:

// Java program to demonstrate 
// PushbackReader skip(long) method 
  
import java.io.*; 
import java.util.*; 
  
class GFG { 
    public static void main(String[] args) 
    { 
  
        try { 
            // Initializing a StringReader 
            // and PushbackReader 
            String s = "GFG"; 
  
            StringReader stringReader 
                = new StringReader(s); 
            PushbackReader pushbackReader 
                = new PushbackReader(stringReader); 
  
            // Get the character 
            // to be read from the stream 
            int ch; 
  
            // Read the first character 
            // to this reader using read() method 
            // This will put the str in the stream 
            // till it is read by the reader 
            ch = pushbackReader.read(); 
            System.out.print((char)ch); 
  
            System.out.println(); 
  
            // skip 1 characters using skip(long) 
            pushbackReader.skip(1); 
  
            System.out.println("Next 1 characters skipped."); 
  
            // Read the next 1 character 
            // to this reader using read() method 
            for (int i = 0; i < 1; i++) { 
                ch = pushbackReader.read(); 
                System.out.print((char)ch); 
            } 
  
            System.out.println(); 
  
            // Close the stream 
            pushbackReader.close(); 
            System.out.println("Stream Closed."); 
        } 
        catch (Exception e) { 
            System.out.println(e); 
        } 
    } 
}
输出:
G
Next 1 characters skipped.
G
Stream Closed.

参考: https://docs.oracle.com/javase/9/docs/api/java/io/PushbackReader.html#skip-long-



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注:本文由纯净天空筛选整理自srinam大神的英文原创作品 PushbackReader skip(long) method in Java with Examples。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。