定义和用法
这个mysqli_stmt_error()函数返回执行最后一条语句期间发生的错误的描述。
用法
mysqli_stmt_error($stmt)
参数
Sr.No | 参数及说明 |
---|---|
1 |
stmt(Mandatory) 这是一个表示语句的对象。 |
返回值
PHP mysqli_stmt_error() 函数返回一个字符串值,表示在执行最后一条语句期间发生的错误的描述。如果没有错误,此函数返回一个空字符串。
PHP版本
这个函数最初是在 PHP 版本 5 中引入的,适用于所有后续版本。
示例
以下示例演示了 mysqli_stmt_error() 函数的用法(程序风格) -
<?php
$con = mysqli_connect("localhost", "root", "password", "mydb");
mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
print("Table Created.....\n");
mysqli_query($con, "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
print("Record Inserted.....\n");
$stmt = mysqli_prepare($con, "SELECT * FROM myplayers");
mysqli_query($con, "DROP TABLE myplayers");
//Executing the statement
mysqli_stmt_execute($stmt);
//Error
$error = mysqli_stmt_error($stmt);
print("Error:".$error);
//Closing the statement
mysqli_stmt_close($stmt);
//Closing the connection
mysqli_close($con);
?>
这将产生以下结果 -
Table Created..... Record Inserted..... Error:Table 'mydb.myplayers' doesn't exist
示例
在面向对象风格中,这个函数的语法是 $con ->error。以下是面向对象风格的此函数的示例 -
<?php
//Creating a connection
$con = new mysqli("localhost", "root", "password", "mydb");
$con -> query("CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
print("Table Created.....\n");
$con -> query("INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
print("Record Inserted.....\n");
$stmt = $con ->prepare("SELECT * FROM myplayers");
$con ->query("DROP TABLE myplayers");
//Executing the statement
$stmt->execute();
//Error
$error = $stmt ->error;
print("Error:".$error);
//Closing the statement
$stmt->close();
//Closing the connection
$con->close();
?>
这将产生以下结果 -
Table Created..... Record Inserted..... Error:Table 'mydb.myplayers' doesn't exist
示例
如果最后执行的语句对象中没有错误,则此函数返回一个空字符串 -
<?php
$con = mysqli_connect("localhost", "root", "password", "mydb");
mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
print("Table Created.....\n");
$query = "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India'),(2, 'Jonathan', 'Trott', 'CapeTown', 'SouthAfrica'),(3, 'Kumara', 'Sangakkara', 'Matale', 'Srilanka')";
//Preparing a statement
$stmt = mysqli_prepare($con, $query);
//Executing the statement
mysqli_stmt_execute($stmt);
print("Record Inserted.....\n");
//Error
$error = mysqli_stmt_error($stmt);
print("Error:".$error);
//Closing the statement
mysqli_stmt_close($stmt);
//Closing the connection
mysqli_close($con);
?>
这将产生以下结果 -
Table Created..... Record Inserted..... Error:
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注:本文由纯净天空筛选整理自 PHP mysqli_stmt_error() Function。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。