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PHP mysqli_stmt_errno()用法及代码示例



定义和用法

这个mysqli_stmt_errno()函数返回执行最后一条语句期间发生的错误的代码。

用法

mysqli_stmt_errno($stmt)

参数

Sr.No 参数及说明
1

stmt(Mandatory)

这是一个表示语句的对象。

返回值

PHP mysqli_stmt_errno() 函数返回一个整数值,表示执行最后一条语句时的错误代码。如果没有错误,此函数返回 0。

PHP版本

这个函数最初是在 PHP 版本 5 中引入的,适用于所有后续版本。

示例

以下示例演示了 mysqli_stmt_errno() 函数的用法(程序风格) -

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");
   mysqli_query($con, "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
   print("Record Inserted.....\n");

   $stmt = mysqli_prepare($con, "SELECT * FROM myplayers");

   mysqli_query($con, "DROP TABLE myplayers");

   //Executing the statement
   mysqli_stmt_execute($stmt);

   //Error Code
   $code = mysqli_stmt_errno($stmt);
   print("Error Code:".$code);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);
?>

这将产生以下结果 -

Table Created.....
Record Inserted.....
Error Code:1146

示例

在面向对象风格中,这个函数的语法是 $stmt ->errno。以下是面向对象风格的此函数的示例 -

<?php
   //Creating a connection
   $con = new mysqli("localhost", "root", "password", "mydb");

   $con -> query("CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");
   $con -> query("INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
   print("Record Inserted.....\n");

   $stmt = $con ->prepare("SELECT * FROM myplayers");

   $con ->query("DROP TABLE myplayers");

   //Executing the statement
   $stmt->execute();

   //Error Code
   $code = $stmt ->errno;
   print("error Code:".$code);

   //Closing the statement
   $stmt->close();

   //Closing the connection
   $con->close();

?>

这将产生以下结果 -

Table Created.....
Record Inserted.....
error Code:1146

示例

如果最后执行的语句对象中没有错误,则此函数返回 0 -

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");

   query = "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India'),(2, 'Jonathan', 'Trott', 'CapeTown', 'SouthAfrica'),(3, 'Kumara', 'Sangakkara', 'Matale', 'Srilanka')";

   //Preparing a statement
   $stmt = mysqli_prepare($con, $query);

   //Executing the statement
   mysqli_stmt_execute($stmt);
   print("Record Inserted.....\n");


   //Error Code
   $code = mysqli_stmt_errno($stmt);
   print("Error Code:".$code);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);
?>

这将产生以下结果 -

Table Created.....
Record Inserted.....
Error Code:0

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注:本文由纯净天空筛选整理自 PHP mysqli_stmt_errno() Function。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。