Java中OffsetDateTime类的withDayOfYear()方法返回此OffsetDateTime的副本,其中year-of-month如参数中所述进行了更改。
用法:
public OffsetDateTime withDayOfYear(int dayOfYear)
参数:此方法接受单个参数dayOfYear,该参数指定要在结果中设置的day-of-year,范围从1到365-366。
返回值:它基于此日期返回OffsetDateTime,其中包含请求的年份,而不是null。
异常:当day-of-year值无效或该特定年份的月份的day-of-year无效时,程序将引发DateTimeException。
以下示例程序旨在说明withDayOfYear()方法:
示例1:
// Java program to demonstrate the withDayOfYear() method
import java.time.OffsetDateTime;
import java.time.ZonedDateTime;
public class GFG {
public static void main(String[] args)
{
// Parses the date1
OffsetDateTime date1
= OffsetDateTime
.parse(
"2018-12-12T13:30:30+05:00");
// Prints dates
System.out.println("Date1: " + date1);
// Changes the day of year
System.out.println("Date1 after altering day-of-year: "
+ date1.withDayOfYear(32));
}
}
输出:
Date1: 2018-12-12T13:30:30+05:00 Date1 after altering day-of-year: 2018-02-01T13:30:30+05:00
示例2:
// Java program to demonstrate the withDayOfYear() method
import java.time.OffsetDateTime;
public class GFG {
public static void main(String[] args)
{
try {
// Parses the date1
OffsetDateTime date1
= OffsetDateTime
.parse(
"2018-12-12T13:30:30+05:00");
// Prints dates
System.out.println("Date1: " + date1);
// Changes the day of year
System.out.println("Date1 after altering day-of-year: "
+ date1.withDayOfYear(367));
}
catch (Exception e) {
System.out.println("Exception: " + e);
}
}
}
输出:
Date1: 2018-12-12T13:30:30+05:00 Exception: java.time.DateTimeException: Invalid value for DayOfYear (valid values 1 - 365/366): 367
参考: https://docs.oracle.com/javase/10/docs/api/java/time/OffsetDateTime.html#withDayOfYear(int)
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注:本文由纯净天空筛选整理自gopaldave大神的英文原创作品 OffsetDateTime withDayOfYear() method in Java with examples。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。