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Java LocalDate withDayOfYear()用法及代码示例

Java中LocalDate类的withDayOfYear()方法返回已更改day-of-year的此LocalDate的副本。

用法:

public LocalDate withDayOfYear(int dayOfYear)

参数:此方法接受必需的参数dayOfYear,该参数指定要在结果中设置的day-of-year,范围为1至365-366。


返回值:该函数基于此日期和所请求的日期返回LocalDate,而不是null。

异常:当day-of-year值无效时,该函数引发DateTimeException。

以下示例程序旨在说明LocalDate.withDayOfYear()方法:

示例1:

// Program to illustrate the withDayOfYear() method 
  
import java.util.*; 
import java.time.*; 
  
public class GfG { 
    public static void main(String[] args) 
    { 
  
        // Parses the date 
        LocalDate dt1 = LocalDate.parse("2018-12-07"); 
        LocalDate result = dt1.withDayOfYear(01); 
  
        // Prints the date with year 
        System.out.println("The date with day of year is: " + result); 
    } 
}
输出:
The date with day of year is: 2018-01-01

示例2:

// Program to illustrate the withDayOfYear() method 
// Exceptions 
import java.util.*; 
import java.time.*; 
import java.time.temporal.ChronoField; 
  
public class GfG { 
    public static void main(String[] args) 
    { 
  
        try { 
            // Parses the date 
            LocalDate dt1 = LocalDate.parse("2018-12-07"); 
            LocalDate result = dt1.withDayOfYear(370); 
  
            // Prints the date with year 
            System.out.println("The date with month is: " + result); 
        } 
        catch (Exception e) { 
            System.out.println(e); 
        } 
    } 
}
输出:
java.time.DateTimeException: Invalid value for DayOfYear (valid values 1 - 365/366): 370

参考: https://docs.oracle.com/javase/10/docs/api/java/time/LocalDate.html#withDayOfYear(int)



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