关于：
numpy.tile(arr, repetitions) : 通过重复数组“ arr”来构造新的数组，“ arr”是我们希望根据重复重复的次数。结果数组的维数为max(arr.ndim，repetitions)，其中，repeats是重复的长度。
如果arr.ndim>重复，则通过在其前面加1来将代表提升为arr.ndim。
如果arr.ndim
参数：
array : [array_like]Input array. repetitions : No. of repetitions of arr along each axis.
返回：
An array with repetitions of array - arr as per d, number of times we want to repeat arr
代码1：
# Python Program illustrating
# numpy.tile()
import numpy as geek
#Working on 1D
arr = geek.arange(5)
print("arr : \n", arr)
repetitions = 2
print("Repeating arr 2 times : \n", geek.tile(arr, repetitions))
repetitions = 3
print("\nRepeating arr 3 times : \n", geek.tile(arr, repetitions))
# [0 1 2 ..., 2 3 4] means [0 1 2 3 4 0 1 2 3 4 0 1 2 3 4]
# since it was long output, so it uses [ ... ]输出：
arr : [0 1 2 3 4] Repeating arr 2 times : [0 1 2 3 4 0 1 2 3 4] Repeating arr 3 times : [0 1 2 ..., 2 3 4]
代码2：
# Python Program illustrating
# numpy.tile()
import numpy as geek
arr = geek.arange(3)
print("arr : \n", arr)
a = 2
b = 2
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
a = 3
b = 2
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
a = 2
b = 3
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)输出：
arr : [0 1 2] Repeating arr : [[0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape : (2, 6) Repeating arr : [[0 1 2 0 1 2] [0 1 2 0 1 2] [0 1 2 0 1 2]] arr Shape : (3, 6) Repeating arr : [[0 1 2 ..., 0 1 2] [0 1 2 ..., 0 1 2]] arr Shape : (2, 9)
代码3 :(重复== arr.ndim)== 0
# Python Program illustrating
# numpy.tile()
import numpy as geek
arr = geek.arange(4).reshape(2, 2)
print("arr : \n", arr)
a = 2
b = 1
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
a = 3
b = 2
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)
a = 2
b = 3
repetitions = (a, b)
print("\nRepeating arr : \n", geek.tile(arr, repetitions))
print("arr Shape : \n", geek.tile(arr, repetitions).shape)输出：
arr : [[0 1] [2 3]] Repeating arr : [[0 1] [2 3] [0 1] [2 3]] arr Shape : (4, 2) Repeating arr : [[0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3] [0 1 0 1] [2 3 2 3]] arr Shape : (6, 4) Repeating arr : [[0 1 0 1 0 1] [2 3 2 3 2 3] [0 1 0 1 0 1] [2 3 2 3 2 3]] arr Shape : (4, 6)
参考文献：
https://docs.scipy.org/doc/numpy/reference/generated/numpy.tile.html
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注：本文由纯净天空筛选整理自 numpy.tile() in Python。非经特殊声明，原始代码版权归原作者所有，本译文未经允许或授权，请勿转载或复制。