numpy.eye(R,C = None,k = 0,dtype = type):返回对角线为1且其他位置为0的矩阵。 k。
参数:
R : Number of rows C : [optional] Number of columns; By default M = N k : [int, optional, 0 by default] Diagonal we require; k>0 means diagonal above main diagonal or vice versa. dtype : [optional, float(by Default)] Data type of returned array.
返回值:
array of shape, R x C, an array where all elements are equal to zero, except for the k-th diagonal, whose values are equal to one.
# Python Programming illustrating
# numpy.eye method
import numpy as geek
# 2x2 matrix with 1's on main diagnol
b = geek.eye(2, dtype = float)
print("Matrix b : \n", b)
# matrix with R=4 C=5 and 1 on diagnol
# below main diagnol
a = geek.eye(4, 5, k = -1)
print("\nMatrix a : \n", a)
输出:
Matrix b : [[ 1. 0.] [ 0. 1.]] Matrix a : [[ 0. 0. 0. 0. 0.] [ 1. 0. 0. 0. 0.] [ 0. 1. 0. 0. 0.] [ 0. 0. 1. 0. 0.]]
注意:
这些代码无法在online-ID上运行。请在您的系统上运行它们以探索工作原理
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注:本文由纯净天空筛选整理自 numpy.eye() in Python。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。