numpy.arcsin(x [,out])= ufunc'arcsin'):此数学函数可帮助用户计算所有x(作为数组元素)的反正弦值。
参数:
array : [array_like]elements are in radians. out : [array_like]array of same shape as x.
返回:
An array with inverse sine of x for all x i.e. array elements. The values are in the closed interval [-pi/2, pi/2].
代码1:工作
# Python program explaining
# arcsin() function
import numpy as np
in_array = [0, 1, 0.3, -1]
print ("Input array : \n", in_array)
arcsin_Values = np.arcsin(in_array)
print ("\nInverse Sine values : \n", arcsin_Values)
输出:
Input array : [0, 1, 0.3, -1] Inverse Sine values : [ 0. 1.57079633 0.30469265 -1.57079633]
代码2:图形表示
# Python program showing
# Graphical representation of
# arcsin() function
import numpy as np
import matplotlib.pyplot as plt
in_array = np.linspace(-np.pi, np.pi, 12)
out_array1 = np.sin(in_array)
out_array2 = np.arcsin(in_array)
print("in_array : ", in_array)
print("\nout_array with sin : ", out_array1)
print("\nout_arraywith arcsin : ", out_array1)
# red for numpy.arcsin()
plt.plot(in_array, out_array1,
color = 'blue', marker = "*")
plt.plot(in_array, out_array2,
color = 'red', marker = "o")
plt.title("blue : numpy.sin() \nred : numpy.arcsin()")
plt.xlabel("X")
plt.ylabel("Y")
plt.show()
输出:
in_array : [-3.14159265 -2.57039399 -1.99919533 -1.42799666 -0.856798 -0.28559933 0.28559933 0.856798 1.42799666 1.99919533 2.57039399 3.14159265] out_array with sin : [ -1.22464680e-16 -5.40640817e-01 -9.09631995e-01 -9.89821442e-01 -7.55749574e-01 -2.81732557e-01 2.81732557e-01 7.55749574e-01 9.89821442e-01 9.09631995e-01 5.40640817e-01 1.22464680e-16] out_arraywith arcsin : [ -1.22464680e-16 -5.40640817e-01 -9.09631995e-01 -9.89821442e-01 -7.55749574e-01 -2.81732557e-01 2.81732557e-01 7.55749574e-01 9.89821442e-01 9.09631995e-01 5.40640817e-01 1.22464680e-16] RuntimeWarning: invalid value encountered in arcsin out_array2 = np.arcsin(in_array)
参考文献:
https://docs.scipy.org/doc/numpy-dev/reference/generated/numpy.arcsin.html#numpy.arcsin
。
相关用法
注:本文由纯净天空筛选整理自Mohit Gupta_OMG 大神的英文原创作品 numpy.arcsin() in Python。非经特殊声明,原始代码版权归原作者所有,本译文未经允许或授权,请勿转载或复制。